Answer:
jkshk
Step-by-step explanation:
jdhhkhjkhjjhgghhh
Answer:
C: 1 over 7 to the 2nd power
Step-by-step explanation:
The question is: 
When multiplying exponents, the base stays the same, while the power is added. In this question, the powers are 3 and -5.
The exponent will become: 
Since the power is negative, it is improper. The negative can be removed by moving the power down and making it a fraction over 1.
The answer is 
, also written as "1 over 7 to the 2nd power".
The first one is
left at 2(A + B)
The second one is
A^2 + 2AB + B^2 The expanded version is greater than A^2 + B^2 See below for why.
(A + B)^2 / [2(A + B) ] = (A + B)/2 which is what is left over when (A + B)^2 is divided by the first one.
(A + B)^2 / (A^2 - B^2) = (A + B) * (A + B) / [(A + B) (A - B)] = (A + B) / (A - B) which is less than (A + B)/2 for (A - B)>2
The third one is just A^2 + B^2 which is smaller than the second one by an amount equal to 2AB. Since A and B are both > 0, 2 AB must be > 0
A^2 - B^2
