Can you show all the numbers so I could do the math
The first line equation: y = -2/7x - 5; m1 = -7/2
The second line passes through (2,4) and is perpendicular to the first line.
Therefore,
The gradient of first line = -1/m1 = -1/(-2/7) = 7/2
Then, the equation of the second line is;
y = 7/2x+b
Substituting for the coordinates given;
4 = 7/2(2)+b
4 = 7+b
b = 4-7 = -3
Therefore, the equation of the second line is;
y = 7/2x - 3
In standard form, the equation this equation can be written as:
y(2) = 7x - 3(2)
2y = 7x - 6
7x -2y - 6 = 0 -----> standard form.
Times oth sides by 100
100d=r(100-x)
divide both sides by (100-x)
Answer:
(x + 1)(x - 1) (x- 2)(x - 5)
Step-by-step explanation:
<u>Solving in steps:</u>
- x^4 - 7x^3 + 9x² + 7 x – 10=
- (x^4 - 1 )- (7x^3 - 7x) + (9x^2 - 9) =
- (x^2 + 1)(x^2 - 1) - 7x(x^2 - 1) + 9(x^2 - 1) =
- (x^2-1)(x^2 + 1 - 7x + 9) =
- (x + 1)(x - 1)(x^2 - 7x + 10) =
- (x + 1)(x - 1)((x^2 - 2x) - (5x - 10)) =
- (x + 1)(x - 1) (x- 2)(x - 5)
Answer:
Literally nothing.
Step-by-step explanation:
Lol
