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Crank
2 years ago
8

Hey yall what all yall doing for extracurricular activities

Mathematics
1 answer:
Law Incorporation [45]2 years ago
6 0

Answer:

Literally nothing.

Step-by-step explanation:

Lol

You might be interested in
Find the length of the missing side of the triangle below.
qaws [65]

let's call the red triangle R, and the blue triangle B.

big/small

2.5/1.75 = 1.43 (rounded)

1.6/1.12 = 1.43 (rounded)

<u>missing side:</u> 2.35 x 1.43 = 3.36

5 0
3 years ago
Solve for x. The triangles in each pair are similar.
pishuonlain [190]
Start off by knowing that the two triangle are congruent. By knowing this you can turn the given numbers into fractions.

9/72 = 7/7x+7

then cross multiply, which equals

63x + 63 = 504

then solve this equation

63x = 441 - subtract 63 from both sides
x = 7 - divide by 63 from both sides

so your answer is x=7
6 0
3 years ago
Need help ASAP please
pochemuha

Answer:

B

Step-by-step explanation:

7 0
3 years ago
HELP!! I'm not sure what goes in the blank.
natta225 [31]

Answer:

10sin^{2} (β)

Step-by-step explanation:

We can find this two ways, first by seeing in the step after it, cosines are canceled out. Since you already have 10sin^{2} (β) on the next step, you can assume that (since only the cosines changed and the cosine next ot the blank was removed), the value is 10sin^{2} (β).

You can also use double angle formulas from the previous step:

(sin(2β) = 2 sin(β) cos(β))and find that:

5 sin (2β) sin(β) = 5 * (2 sin(β) cos(β)) sin(β)) = (10 sin(β) sin(β)) cos(β) =

10sin^{2} (β) cos(β)

But since cos(β) is already present, we can see that the answer is 10sin^{2} (β)

4 0
2 years ago
PLEASE PLEASE PLEASE HELP ME
lubasha [3.4K]

Answer:

CE = 17

Step-by-step explanation:

∵ m∠D = 90

∵ DK ⊥ CE

∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK

In the two Δ KDE and KCD:

∵ m∠KDE = m∠KCD

∵ m∠DKE = m∠CKD

∵ DK is a common side

∴ Δ KDE is similar to ΔKCD

∴ \frac{KD}{KC}=\frac{DE}{CD}=\frac{KE}{KD}

∵ DE : CD = 5 : 3

∴ \frac{KD}{KC}=\frac{5}{3}

∴ KD = 5/3 KC

∵ KE = KC + 8

∵ \frac{KE}{KD}=\frac{5}{3}

∴ \frac{KC+8}{\frac{5}{3}KC }=\frac{5}{3}

∴ KC + 8 = \frac{25}{9}KC

∴ \frac{25}{9}KC - KC=8

∴ \frac{16}{9}KC=8

∴ KC = (8 × 9) ÷ 16 = 4.5

∴ KE = 8 + 4.5 = 12.5

∴ CE = 12.5 + 4.5 = 17

7 0
3 years ago
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