let's call the red triangle R, and the blue triangle B.
big/small
2.5/1.75 = 1.43 (rounded)
1.6/1.12 = 1.43 (rounded)
<u>missing side:</u> 2.35 x 1.43 = 3.36
Start off by knowing that the two triangle are congruent. By knowing this you can turn the given numbers into fractions.
9/72 = 7/7x+7
then cross multiply, which equals
63x + 63 = 504
then solve this equation
63x = 441 - subtract 63 from both sides
x = 7 - divide by 63 from both sides
so your answer is x=7
Answer:
B
Step-by-step explanation:
Answer:
10
β
Step-by-step explanation:
We can find this two ways, first by seeing in the step after it, cosines are canceled out. Since you already have 10
β
on the next step, you can assume that (since only the cosines changed and the cosine next ot the blank was removed), the value is 10
β
.
You can also use double angle formulas from the previous step:
(sin(2β) = 2 sin(β) cos(β))and find that:
5 sin (2β) sin(β) = 5 * (2 sin(β) cos(β)) sin(β)) = (10 sin(β) sin(β)) cos(β) =
10
β
cos(β)
But since cos(β) is already present, we can see that the answer is 10
β
Answer:
CE = 17
Step-by-step explanation:
∵ m∠D = 90
∵ DK ⊥ CE
∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK
In the two Δ KDE and KCD:
∵ m∠KDE = m∠KCD
∵ m∠DKE = m∠CKD
∵ DK is a common side
∴ Δ KDE is similar to ΔKCD
∴ 
∵ DE : CD = 5 : 3
∴ 
∴ KD = 5/3 KC
∵ KE = KC + 8
∵ 
∴ 
∴ 
∴ 
∴ 
∴ KC = (8 × 9) ÷ 16 = 4.5
∴ KE = 8 + 4.5 = 12.5
∴ CE = 12.5 + 4.5 = 17