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Viefleur [7K]
3 years ago
12

The specification for the pull strength of a wire that connects an integrated circuit to its frame is 10 g or more. Units made w

ith aluminum wire have a defect rate of 10%. A redesigned manufacturing process involving the use of gold wire is being investigated. The goal is to reduce the rate of defects to 5% or less. Out of the first 100 units manufactured with gold wire, only 4 are defective. True or false:
Business
1 answer:
Zepler [3.9K]3 years ago
5 0

Answer:

Since 4 is less 5, it is therefore True that only 4 are defective.

Explanation:

Since the goal of using the gold wire is to reduce the rate of defects to 5% or less, the highest number of defective units from the first 100 units manufactured with gold wire can be calculated as follows:

Highest number of defective units using gold wire = Number of units manufactured with gold wire * Highest defective rate ..................... (1)

Where;

Number of units manufactured with gold wire = 100

Highest defective rate using gold wire = 5%

Substituting the values into equation (1), we have:

Highest number of defective units using gold wire = 100 * 5% = 5

Based on the calculation above, it implies that the number of defective units from the first 100 units manufactured with gold wire is less or equal to 5.

Since 4 is less 5, it is therefore True that only 4 are defective.

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Rodney Cashman has been investing $2,000 quarterly for the past 18 years in an equity mutual fund. How much is the fund worth no
leva [86]

Answer:

<em>Rodney Cashman's fund is worth $ 465,862.95 after investing for the past 18 years.</em>

Explanation:

Given: Number of periods - 18 years * 4 quarters = 72

Periodic payment - $2,000

Interest Rate - 11.5%

Formula: FV of Annuity= p [(1+ r/m)n-1/ (r/m)]

Where:

P - Periodic Payment

r - interest rate

n - number of periods

m - compounding period

FV of Annuity =$ 465,862.95

4 0
3 years ago
What is the most important thing about meeting new contacts? A. Building your Rolodex B. Overcoming shyness C. Getting referrals
Neporo4naja [7]
<span>The answer is A . Forming relationships is the most important thing about meeting new contacts.</span>
3 0
4 years ago
XZYY, Inc. currently has an issue of bonds outstanding that will mature in 31 years. The bonds have a face value of $1,000 and a
Mamont248 [21]

Answer:

7.31%

Explanation:

The question is pointing at the bond's yield to maturity.

The yield to maturity can be computed using the rate formula in excel as provided below:

=rate(nper,pmt,-pv,fv)

nper is the number of times the bond would pay annual coupons which is 31

pmt is the annual coupon payment i.e $1000*8.0%=$80.00

pv is the current price of the bond which is $1,084

fv is the face value of the bond which is $1,000

=rate(31,80,-1084,1000)=7.31%

The yield to maturity is 7.31%

That is the annual rate of return for an investor that holds the bond till maturity.

3 0
3 years ago
Pioneering advertisements would most likely be used during which stage of the product life cycle?
abruzzese [7]

Answer:

(1) introduction

Explanation:

Pioneering advertising creates consumers awareness about the availability of a totally new product as well as explaining its use.

3 0
4 years ago
If the monthly income of the IBM employees follows a SYMMETRICAL NORMAL distribution, with a median of $5000 and a standard devi
AURORKA [14]

Answer:  mean monthly income = $5000

====================================================

Explanation

In any normal distribution, the median and mean are the same value.

-------------

The proof is as follows:

If mean > median was the case, then the distribution would be skewed to the right (ie positively skewed). The right tail is pulled longer than the left tail. But this would contradict the symmetrical nature of the normal distribution. So mean > median must not be the case.

If mean < median, then the distribution would be skewed to the left (negatively skewed). Visually this pulls the left tail longer than the right tail. Like in the previous paragraph, this contradicts the symmetrical nature of the normal distribution. So mean < median must not be the case.

Since mean > median cannot be true, and neither can mean < median, this must indicate mean = median.

-------------

So in short, any symmetrical distribution always has mean = median and they are at the very center of the distribution.

4 0
3 years ago
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