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gulaghasi [49]
3 years ago
13

Raina has 3 buckets.

Mathematics
1 answer:
Daniel [21]3 years ago
4 0

Answer:

30/3=10

so every bucket gets 10 liters

Step-by-step explanation:

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Can someone pls help me <br> Ill give Brainly<br> NO BOTS OR ILL REPORT YOU
tankabanditka [31]
The first one 3y = 2x - 12.

The graph is the line y = 2/3 - 4. And the first answer describes the same line multipled by 3.
7 0
2 years ago
Mr. Zelman wants to give 50% of his comic book collection to his nephew Alex. If Mr. Zelman has 800 comic books, then how many w
BARSIC [14]

Mr. Zelman gave 400 books to his nephew

<em><u>Solution:</u></em>

Given that, Mr. Zelman wants to give 50% of his comic book collection to his nephew Alex

Mr. Zelman has 800 comic books

Number of books with Zelman = 800

Mr. Zelman wants to give 50% of books to Alex

Number of books given to nephew = 50 % of books of Zelman

Therefore, we have to find 50 % of 800

\rightarrow 50 \% \text{ of } 800

\rightarrow 50 \% \times 800\\\\\rightarrow \frac{50}{100} \times 800 = 400

Thus he gave 400 books to his nephew

4 0
3 years ago
Can some one do this for me
Mama L [17]

Answer:

1)13(left)

2)52(right)

3)48

4)51.923

Step-by-step explanation:

a^2+b^2=C^2

3 0
3 years ago
Read 2 more answers
F(x)= 13,500 .89x, is this growing or decay
Oksanka [162]
I hope and think it’s 12015
Because this what I did I (.89)x
And x = 13500 and I got 12015
8 0
3 years ago
A customer works into a post office to purchase stamps. she purchases a total of 45 stamps. some of the stamps are 49cent stamps
baherus [9]

Step-by-step explanation:Let number of 49 cents =A

                                             Let number of 33 cents=B

<u>A+B=45    equation 1</u>

1 $=100 cents

49 cents =.49 dollar

33 cents=.33 dollar

so .<u>49A+.33B=17.89    equation 2</u>

Add equation 1 and equation 2

since these are simultaneous equations

.49A+.33B=17.89

     A+     B=45

so divide equation 2 by 100 we get

49A+33B=1789

    A+B     =45 multiply equation 1 by 33 on both the sides we get

<u>33A+33B=1485     equation 3</u>

so subtract equation 3 from equation 2 we get

49A+33B=1789  equation 2

<u>33A+33B=1485    equation 3</u>

<u>16A+0      =304</u>

16A=304

A=304/16

A=19

putting nalue of A in equation 1 we get

A+B=45

19+B=45

B=45-19

B=26

so number of 49 cent stamps are 19

and number of 33 cent stamps are 26

5 0
2 years ago
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