The vertical asymptotes of the function are 3 and 6
Given the function
The vertical asymptotes of the function occur at the point where the <u>denominator is zero.</u>
Equate the denominator to zero.
x^2 - 9x + 18 = 0
Factorize the quadratic expression:
x^2 - 3x - 6x + 18 =0
x(x-3)-6(x-3) = 0
(x-3)(x-6) = 0
x - 3 = 0 and x - 6 = 0
x = 3 and 6
Hence the vertical asymptotes of the function are 3 and 6
Learn more on vertical asymptotes here: brainly.com/question/21678319
RT + tw = wx + tw is the right answer
Answer:
x=2/3
Step-by-step explanation:
6x=3x+2
3x=2
x=2/3
No!
Because I don't know but I tried:
2/5= 0.4 and 3/5= 0.6, they are not equal so if Yvonne says he did 2/5 of a problem each minute, and then she will be correct!
Set both equations equal to each other
2x + 2 = 3x - 52 (Get x by itself)
+52 +52
2x +54 = 3x
-2x -2x
54 = x
Hope this helps :)