To find the hypotenuse of a right triangle, you must use a^2 + b^2 = c^2
* keep in mind the hypotenuse MUST be larger than the legs.
The Pythagorean Theorem comes from making 2 squares from the lengths of each leg (that is why it is a^2 and b^2). The hypotenuse must be equal to the area of the two squares created.
To solve this, simply substiture 8 in for x, and solve for y.
11(8) -6y = -1
Multiply 11 by 8
88 - 6y = -1
Subtract 88 from each side of the equation.
-6y = -89
Lastly divide each side of the equation by -6
y = 89/6 is your answer.
Hope this helps!
Answer:
Step-by-step explanation:
If
τ
1
and
τ
2
are two typologies on non-empty set
X
, then ………………. is topological space.
Answer:
Step-by-step explanation:
Let the first number = x
Let the second number = x + 9
Let the third number = 4x
Together they make 123
x + x + 9 + 4x = 123 combine the left
6x + 9 = 123 Subtract 9 from both sides
6x = 123 - 9
6x = 114 Divide by 6
x = 114/6
x = 19
=================
First number = 19
Second number = 19 + 9 = 28
Third number = 4*19 = 76
Answer:
The probability is 0.3576
Step-by-step explanation:
The probability for the ball to fall into the green ball in one roll is 2/1919+2 = 2/40 = 1/20. The probability for the ball to roll into other color is, therefore, 19/20.
For 25 rolls, the probability for the ball to never fall into the green color is obteined by powering 19/20 25 times, hence it is 19/20^25 = 0.2773
To obtain the probability of the ball to fall once into the green color, we need to multiply 1/20 by 19/20 powered 24 times, and then multiply by 25 (this corresponds on the total possible positions for the green roll). The result is 1/20* (19/20)^24 *25 = 0.3649
The exercise is asking us the probability for the ball to fall into the green color at least twice. We can calculate it by substracting from 1 the probability of the complementary event: the event in which the ball falls only once or 0 times. That probability is obtained from summing the disjoint events: the probability for the ball falling once and the probability of the ball never falling. We alredy computed those probabilities.
As a result. The probability that the ball falls into the green slot at least twice is 1- 0.2773-0.3629 = 0.3576
