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Y_Kistochka [10]
3 years ago
15

HELP ME PLZZZZZZZZZZZZZZZZZ

Mathematics
2 answers:
Andre45 [30]3 years ago
5 0

Answer:

4

Step-by-step explanation:

Have a nice day!

murzikaleks [220]3 years ago
4 0
The correct answer is 4
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Neal used magnetic letters to spell the word communication on his file cabinet. One of the magnets fell on the floor. What is th
Nataliya [291]

Answer:

the likehood that an n fell on the floor is 2 in 13.

Step-by-step explanation:

8 0
4 years ago
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If ur right I’ll give you brainliest pls help me out :)
brilliants [131]

Answer:

588 in³

Step-by-step explanation:

Break it up in three parts.

Left part: 7*8*3 = 168

Mid part: 6*6*7 = 252

Right part: 7*8*3 = 168

Sum: 168+252+168 = 588

8 0
3 years ago
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Solve each system of equations by graphing y=2/3x+3 3y=2x+15
dangina [55]

Answer:

There is no solution to that equation.

Step-by-step explanation:

First thing to do is to put the second equation in terms of y. To do so the equation becomes y= 2/3x+5. Comparing those two equation you can see that the slopes are the same and thus means that the system has no solution.

Another way to see this is by graphing both of thee equations is a calculator and seeing there are no points of intersection.

7 0
3 years ago
Michaela works in a bank she is paid £19200 per annum how much does she get per month
Step2247 [10]

in a year she earns=19200

So in a month she earns=19200/12

=1600

So she earns 1600 every month.

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4 0
4 years ago
What is the product?
ZanzabumX [31]

Answer:

The product is:

\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]

Step-by-step explanation:

For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:

\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]

1 \times 2 + 3 \times 3 + 1 \times -2 = 15

So the value of the element in the position a_{11} is 15

1 \times -2 + 3 \times 5 + 1 \times 1 = 14

So the value of the element in the position a_{12} is 14

Then with these two values you can determinate the result matrix.

\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]

3 0
2 years ago
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