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almond37 [142]
3 years ago
9

The area of a rectangular painting is given by the trinomial x2 + 4x - 21. What are the possible dimensions of the painting? Use

factoring.
Mathematics
2 answers:
sweet [91]3 years ago
5 0

Answer:

(x+7)\text{ and } (x-3)

Step-by-step explanation:

We have been given an expression x^{2}+4x-21 that represents area of a rectangular painting. We are asked to find the possible dimensions of the painting using factorization.

We will factor our quadratic expression by splitting the middle term.

x^{2}+4x-21

x^{2}+7x-3x-21

x(x+7)-3(x+7)

(x+7)(x-3)

Therefore, the possible dimensions of the painting are (x+7)\text{ and } (x-3).

zloy xaker [14]3 years ago
3 0
To find the dimensions you can just factor the equation...

x^2+4x-21

x^2-3x+7x-21

x(x-3)+7(x-3)

(x+7)(x-3) and this is equal to LW or WL

And note that x>3 for any possible solution.

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Anna71 [15]
Sorry for the late response

(bigger number - smaller number) divided by original number

(251 - 248) / 248
3 / 248           Divide to make this a decimal
0.0120967741...  round it
0.012  change into percent
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hope this helps!

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4 years ago
For the right triangle find the missing length. Round your answer<br> to the nearest tenth.
monitta

Answer:

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3 years ago
A piece of rope can be cut into an exact number of 6 m lengths.
Gnesinka [82]

Answer:

24 m

Step-by-step explanation:

the smallest common multiple of 6 and 8.

I know already what that is (24) based on experience, but let's do this formally via prime factoring :

6 ÷ 2 = 3

3 ÷ 2 no

3 ÷ 3 = 1 finished

8 ÷ 2 = 4

4 ÷ 2 = 2

2 ÷ 2 = 1 finished

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the smallest common multiple is the combination of the longest streaks per prime factor.

and that is 3 times a 2 and 1 time a 3 :

2 × 2 × 2 × 3 = 24 m

5 0
2 years ago
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How many 5-millimeter-long spiders would it take to make a line of spiders 1 meter long?
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Answer:

1000

Step-by-step explanation:

10milimeter=1 centimeter

100 centimeters=1 meter

10x100=1000

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3 0
4 years ago
Find the distance between the points: (–6, 7) and (–1, –5). In your final answer, include the formula and calculations that you
Arturiano [62]

To find distance between points <span>A(<span>xA</span>,<span>yA</span>)</span> and <span>B(<span>xB</span>,<span>yB</span>)</span>, 

formula:

<span>d(A,B)=</span>√ [(xB−xA)^2+(yB−yA)^2]

so distance between the points: (–6, 7) and (–1, –5)<span>
</span>= √ [<span><span><span><span>(<span>−1−<span>(<span>−6</span>)</span></span>)^</span>2 </span>+ <span><span>(<span>−5−7</span>)^</span>2]
</span></span>= </span>√ (<span><span>25+144)
</span>= </span>√ 169
<span><span><span>= </span></span><span>13

answer
13</span></span>
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3 years ago
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