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3 years ago

7

Convert the unit of weight 3/4lb =oz

2 answers:

Ket [755]3 years ago

8 0

Answer:

3/4Ib = 12 ounces!

Step-by-step explanation:

hoped this helped :)

Tomtit [17]3 years ago

8 0

Answer:

3/4lb = 12oz

16oz per lb, multiply 16 by 3/4

16x3/4 = 12

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2. The sum of the reciprocals of two consecutive positive integers is 17/72. Write an equation that can be used to find the two

Lena [83]

To answer this item, we let x be the first positive integer. Then, the second would be x+1. Their reciprocals would be 1/x and 1/(x+1). Then, the equation that would best represent the scenario above is,
1/x + 1/(x+1) = 17/72
Solving the equation above,
((x+1) + x) / (x)(x+1) = 17/72
If we take the numerators of both sides of the equation,
(x+1) + x = 17
The value of x from the equation is 8 and x+1 would be 9. Thus, the answer would be 8 and 9.

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3 years ago

The Green Goober, a wildly unpopular superhero, mixes 3 liters of yellow paint with 5 liters of blue paint to make 8 liters of s

Degger [83]

Let

y------> the amounts (in liters) of yellow paint

b-----> the amounts (in liters) of blue paint

we know that

$\frac{y}{b}=\frac{3}{5}$

so

$y=\frac{3}{5}b$

therefore

<u>the answer is</u>

$y=\frac{3}{5}b$

5 0

3 years ago

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21 ten thousands + 18 ones + 60 hundreds

Vinvika [58]

21,618.........................

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3 years ago

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The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.

andrezito [222]

Answer:

Given the equation: $3x^2+10x+c =0$

A quadratic equation is in the form: $ax^2+bx+c = 0$ where a, b ,c are the coefficient and a≠0 then the solution is given by :

$x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$ ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

$x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}$

Simplify:

$x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}$

Also, it is given that the difference of two roots of the given equation is $4\frac{2}{3} = \frac{14}{3}$

i.e,

$x_1 -x_2 = \frac{14}{3}$

Here,

$x_1 = \frac{-10 + \sqrt{100- 12c}}{6}$ , ......[2]

$x_2= \frac{-10 - \sqrt{100- 12c}}{6}$ .....[3]

then;

$\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}$

simplify:

$\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}$

or

$\sqrt{100- 12c} = 14$

Squaring both sides we get;

$100-12c = 196$

Subtract 100 from both sides, we get

$100-12c -100= 196-100$

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve $x_1 , x_2$

$x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}$

or

$x_1 = \frac{-10 + \sqrt{100- 96}}{6}$ or

$x_1 = \frac{-10 + \sqrt{4}}{6}$

Simplify:

$x_1 = \frac{-4}{3}$

Now, to solve for $x_2$ ;

$x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}$

or

$x_2 = \frac{-10 - \sqrt{100- 96}}{6}$ or

$x_2 = \frac{-10 - \sqrt{4}}{6}$

Simplify:

$x_2 = -2$

therefore, the solution for the given equation is: $-\frac{4}{3}$ and -2.

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3 years ago

4. Factor Completely *<br> (1 Point)<br> 5x3 + 40x2 - 2x - 16

mart [117]

Answer:

(x+8)(5x2−2)

Step-by-step explanation:

Hope this helps have a nice day :)

4 0

3 years ago