Question

Can someone please answer this, ill give you brainliest Would be very appreciated.

Answer 1

Answer:

Given function:

f(t) = (-16t - 2)(t - 1)

Part 1

The zeros of the function are the values of t when f(t) = 0

⇒ f(t) = 0

⇒ (-16t - 2)(t - 1) = 0

⇒ (t - 1) = 0  ⇒  t = 1

⇒ (-16t - 2) = 0  ⇒ t = -2/16 = -1/8

Part 2

The zeroes tell us the time (in seconds) when the ball is at ground level (when its height is zero).

Since time is not negative, only one zero is meaningful:  t = 1

Therefore, the total journey of the ball, from throwing it to it hitting the ground, is 1 second.

Part 3

The height the ball is thrown can be determined by inputting t = 0 into the function:

⇒ f(0) = (-16(0) - 2)(0 - 1)

⇒ f(0) = (0 - 2)(0 - 1)

⇒ f(0) = (-2)(-1)

⇒ f(0) = 2

Therefore, the height from which the beach ball is thrown is 2 ft.

Answer 2

Equation: y = (-16t-2)(t -1)

1) Finding zeros of the function?

To find zero's of the function y = 0

(-16t-2)(t -1) = 0

-16t - 2 = 0, t - 1 = 0

t = 2/-16, t = 1

t = -0.125, 1

2) What do the zero's tell us? Are they meaningful?

Answer: It tells us that the time is 1 seconds when the height of the ball is 0 or at rest.

3) From what height is the ball thrown?

Insert t = 0

y = (-16(0)-2)((0) -1)

y = 2

Ball thrown from 2 feet.