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mylen [45]
3 years ago
5

I need help on all of number 2!!!!

Mathematics
2 answers:
erica [24]3 years ago
7 0

9514 1404 393

Answer:

  a: 0; b: 1; c: 1; d: ∞; e: 0; f: ∞

Step-by-step explanation:

Simplify the expressions to put the left and right in the same form. Then compare. If the x-coefficients are the same, there will be 0 or ∞ solutions. If they are different, there will be 1 solution.

If the x-coefficients are the same, look at the constants. If they are different, there will be 0 solutions. If they are the same, there will be ∞ solutions.

__

a) -2x -10 = -6x +4x -8  ⇒  -2x -10 = -2x -8 . . . . 0 solutions

b) 0.8x -4.8 = -0.5x +3.4 . . . . 1 solution

c) -1/4x -7/2 = -3x -4 . . . . 1 solution

d) 2x -8 +x = 3x -6 -2  ⇒  3x -8 = 3x -8 . . . . ∞ solutions

e) 3 -2/5x -12/5 = 2 -2/5x  ⇒  -2/5x +3/5 = -2/5x +2 . . . . 0 solutions

f) 6x -6 +21 = 6x +15  ⇒  6x +15 = 6x +15 . . . . ∞ solutions

guapka [62]3 years ago
5 0

Answer:

a)3x+7x-8=18

3x+7x=18+8

10x=18+8

10x=26

x=13/5

b)-8+2x=12x-3

-8+2x-12x=-3

2x-12x=-3+8

-10x=-3+8

-10x=5

x=-1/2

e)4/3x-18+2/3x=7/3x+9

4x-54+2x=7x+27

6x-54=7x+27

6x-7x-54=27

6x-7x=27+54

-x=27+54

-x=81

X=-81

d)-2x-4/5 +8/5 =3x-3

-2x-4+8=15x-15

-2x+4=15x-5

-2x-15x+4=-15

-2x-15x=-15-4

-17x=-15-4

-17x=-19

x=19/17

Step-by-step explanation:

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3 years ago
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6 0
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If $x$, $y$, and $z$ are positive integers such that $6xyz+30xy+21xz+2yz+105x+10y+7z=812$, find $x+y+z$.
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Answer:

10

Step-by-step explanation:

When we simplify we get $$z(6xy+21x+2y+7)+30xy+105x+10y=812.$$

Then we continue to factor to get: (z+5)(6xy+21x+2y+7)&=847.

We then see that we can factor (6xy+21x+2y+7) into (z+5)(3x+1)(2y+7)&=847.

we then do the prime factorization of 847, which i think is,  7*11*11. we have to find the numbers that multiply to 847 and then plug them into z+5, 3x=1,2y+7.

It has to be a positive, non-negative integer, right?

We also see that 3x+1=11 so we see that x=10/3 (which wont work).

So 3x+1=7, so x=2.

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for the last term we get z+5=11 so z=6

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8 0
4 years ago
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