Answer:
Number 1 is 2 5/14
Step-by-step explanation:
The number of gallons of water in the tank at t=10 is
... W(10) = 160,000 -10(8000 -10) = 80100
The number of gallons of water in the tank at t=10.5 is
... W(10.5) = 160,000 -10.5(8000 -10.5) = 76110.25
The rate of change over the interval is
... (W(10.5) - W(10))/(10.5 - 10) = (76110.25 - 80100)/(0.5) = -7979.5
The average rate of change in the number of gallons of water in the tank over the interval is -7979.5 gal/min.
The sign is negative, so the amount of water is decreasing.
Subtract the minimum data value from the maximum data value to find the data range,so in this case yur data range is
10 - 0.08 = 9.92
so yur answer is 9.92
Answer:
m=3
b=(0,5)
Step-by-step explanation: