Because there is a +e and a -e in the two equations we can simply add them together to solve for d...
2d+e+d-e=8+4 combine like terms
3d=12 divide by 3
d=4, now use this d in either original equation to solve for e...<span>d–e=4 so
4-e=4 subtract 4
-e=0
e=0
So the solution, where the lines intersect graphically, is the point (4, 0)</span>
Answer:
It's a trapezium with a triangle
Answer:
The height of the right circular cylinder is 4.55 inches ⇒ b
Step-by-step explanation:
The formula of the surface area of a right circular cylinder is
S.A = 2πrh + 2πr², where
∵ The surface area of a right circular cylinder is 300 square inches
∴ S.A = 300 in.²
∵ Its radius is 5 inches
∴ r = 5 in.
∵ π = 3.14
→ Substitute them in the rule above
∵ 300 = 2(3.14)(5)(h) + 2(3.14)(5)²
∴ 300 = 31.4h + 157
→ Subtract 157 from both sides
∵ 300 - 157 = 31.4h + 157 - 157
∴ 143 = 31.4h
→ Divide both sides by 31.4
∵ 4.554140127 = h
∴ 4.55 = h
∴ The height of the right circular cylinder is 4.55 inches
Hint to start out the problem:
eg. For f(4), use the first expression, (x-3)^2 because 4 is greater than 1.
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