(15a^4 - 30a^5 )/5a^2
= 5a^2(3a^2 - 6a^3) / 5a^2
= 3a^2 - 6a^3
or
= - 6a^3 + 3a^2
Answer:
Step-by-step explanation:
As an example, iodine-131 is a radioisotope with a half-life of 8 days. It decays by beta particle emission into xenon-131. After eight days have passed, half of the atoms of any sample of iodine-131 will have decayed, and the sample will now be 50% iodine-131 and 50% xenon-131.
50 grams to 25 grams is one half-life. 25 grams to 12.5 grams is another half-life. So, for 50 grams to decay to 12.5 grams, two half-lives, which would take 36 days total, would need to pass. This means each half-life for element X is 18 days.
AG and GB must be congruent and CG and GD must be congruent as well
What you must do in this case is to find the roots of the polynomial.
We have then:
x ^ 2 + 20x + 100 = 36
Rewriting:
x ^ 2 + 20x + 64 = 0
The values of the roots are:
x1 = -4
x2 = -16
Remember that the values of the roots are what make the polinome zero
Answer:
x1 = -4
x2 = -16
25+0.11n>12+0.36n
13>0.25n
n<52
Option b will cheaper then quantity of miles less than 52 miles.
