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AleksAgata [21]
3 years ago
13

I need Help please and thank you !!!!!

Mathematics
2 answers:
blsea [12.9K]3 years ago
7 0
The equation is $58-$32=$26
Molodets [167]3 years ago
7 0
You did it right on the side but you just need to write it sideways so it would be $58-$32=$26
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Your family is going on a road trip to Disney World! On Day 1, you traveled x miles. On Day 2, you drove 58 miles more than 3 ti
Eva8 [605]

Answer:i need help with this also

Step-by-step explanation:

8 0
3 years ago
PLEASE HELP QUICKLY: GEOMETRY
WITCHER [35]

x/230=43/215

your answer would be 46

7 0
3 years ago
Solving Quadratic Equations using the Square Root Property
Afina-wow [57]

Answer:

x = -2   or   x = -5

Step-by-step explanation:

You need to complete the square before you can take the square root of both sides.

x^2 + 7x + 10 = 0

Subtract 10 from both sides.

x^2 + 7x = -10

To complete the square, you need to add the square of half of the x-term coefficient to both sides.

The x-term coefficient is 7. Half of that is 7/2. Square it to get 49/4. Now we add 49/4 to both sides of the equation.

x^2 + 7x + \dfrac{49}{4} = -10 + \dfrac{49}{4}

(x + \dfrac{7}{2})^2 = -\dfrac{40}{4} + \dfrac{49}{4}

(x + \dfrac{7}{2})^2 = \dfrac{9}{4}

Now we use the square root property, if

x^2 = k, then

x = \pm \sqrt{k}

x + \dfrac{7}{2} = \pm \sqrt{\dfrac{9}{4}}

x + \dfrac{7}{2} = \pm \dfrac{3}{2}

x + \dfrac{7}{2} = \dfrac{3}{2}   or   x + \dfrac{7}{2} = -\dfrac{3}{2}

x = -\dfrac{4}{2}   or   x = -\dfrac{10}{2}

x = -2   or   x = -5

5 0
3 years ago
I’m confused on this one
Alenkinab [10]

Remark

I would have had the answer a whole lot sooner if I would have read the question properly. The figure in the circle is called a cyclic quadrilateral. It has the odd property that the angles that are opposite each other add up to 180o.

So DEB + DCB = 180o

DEB = 180 - 87

DEB = 93o

Note: The arcs marked 60 and 76 have nothing whatever to do with this problem.

7 0
3 years ago
NEED ASAP PLEASE HELP
sweet-ann [11.9K]

Answer:

Dilations produce similar figures because the image and pre-image will have congruent corresponding angles. The corresponding side lengths of the figures will be proportional based on the scale factor. The shape is preserved and the sides are enlarged or reduced by the scale factor

Step-by-step explanation:

6 0
2 years ago
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