Step-by-step explanation:
Given, 3x−2<2x+1
⇒3x−2x<1+2
⇒x<3orx∈(−∞,3)
The lines y=3x−2 and y=2x+1 both will intersect at x=3
Clearly, the dark line shows the solution of 3x−2<2x+1.
Answer:
I would say...
C.)x - 5 = 3 (x + 2)
Really really sorry if I'm wrong...
One thing I can say is that when it says 5 less than a #, that means the # is being subtracted from another #...
Answer:
Q' (-2, 2)
P' (-2, 7)
R' (6, 2)
Step-by-step explanation:
When reflecting over a diagnal line such as y = x or y = -x, a trick is to count the boxes at an angle to see how many spaces it is away from the line. Be sure to recipicate what you counted the first time, and when reflecting over y = -x, flip the x and y coordinates and if needed, change the signs.
Hope this helps!
Find the smallest number that is divisible by 2, 3, 4, 5, 6 and add 1.
We need the least common multiple of 2, 3, 4, 5, 6.
2 = 2
3 = 3
4 = 2^2
5 = 5
6 = 2 * 3
LCM = product of common and not common prime factors with larger exponent.
LCM = 2^2 * 3 * 5 = 4 * 3 * 5 = 60
To always have a remainder of 1, you need of add 1 to 60.
The number is 61.
Check:
61/2 = 30 remainder 1
61/3 = 20 remainder 1
61/4 = 15 remainder 1
61/5 = 12 remainder 1
61/6 = 10 remainder 1
Ok so first 2.4 will have to be changed to 24 which means we multiplied it by ten making it 24/10 since it is tan it is opposite side/ adjacent side so your one of your legs will be 24 and one will be 10. Now we just plug that into the Pythagorean Theorem to find the hypotenuse and we get 26. The area is 24b10/2=120 the area is 120.
Leg a= 24
Leg b= 10
Hypotenuse=26
Area=120
Ignore my awful handwriting but this is what it looks like labeled. I made each unit=2 just so it wouldn't be as large but I hope this helps you :)
