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nika2105 [10]
3 years ago
15

How can you use a number line to show that 18 + ( -18) = 0? Plz explain your answer.

Mathematics
1 answer:
cricket20 [7]3 years ago
5 0

The correct answer is B.

Before you start using the number line, you must always keep in mind that:

– and – = +

+ and – = –

+ and + = +

– and + = –

To remember all this you'd also have to keep in mind that all like-terms which are the (– and –) and (+ and +) are both positive or (+). Also, the terms which are not alike such as (– and +) and (+ and –) are negative or (–).

In this problem, we have 2 signs which are (+ and –). As I said above, these terms that are not alike are (–).

On the number line since they're negative, we have to move to the left or subtract. For the opposite of that, we'll have to move to the right or add.

18 + (-18)=0.

To prove this, REMOVE THE BRACKETS and calculate as usual.

18 + - 18 = 0

In this case, we have to SUBTRACT or MOVE TO THE LEFT ON THE NUMBER LINE.

So, the answer is 0 after we subtracted both terms. We do this by:

18 - 18 = 0.

So, we have to:

BEGIN WITH 18 AND MOVE 18 UNITS TO THE LEFT.

Therefore, the answer is B.

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Answer:

The range of the function is:

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Step-by-step explanation:

Given the function

f(x) = 3x + 2

We also know that range is the set of values of the dependent variable for which a function is defined.  

In other words,  

  • Range refers to all the possible sets of output values on the y-axis.

We are given that the domain of the function is:

Domain D = {4, 5, 6}

Now,

substituting x = 4 in the function

f(4) = 3(4) + 2

f(4) = 12 + 2

f(4) = 14

substituting x = 5 in the function

f(5) = 3(5) + 2

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substituting x = 6 in the function

f(6) = 3(6) + 2

f(6) = 18 + 2

f(6) = 20

Thus, we conclude that:

at x = 4, y = 14

at x = 5, y = 17

at x = 6, y = 20

Thus, the range of the function is:

Range R = {14, 17, 20}

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