30=8+4(z-2)
Distribute 4 through the parentheses
30=8+4z-8
Eliminate the opposites
30=4z
Swap the sides of the equation
4z=30
Divide both sides of the equation by 4
4z÷4=30÷4
Any expression divided by itself equals 1
z=30÷4
or write the division as a fraction
z=30/4
copy the numerator and denominator of the fraction
30=2x3x5
4=2x2
Write the prime factorization of 30
Write the prime factorization of 4
30=2 x3x5
4=2x2
2
Line up the common factors in both lists
Copy the common factors
Since there is only one common factor, the common factor 2 is also the greatest common factor
30÷2/4÷2
2
Divide 30 and 4 by the greatest common factor 2
15/4÷2
Divide the numbers in the numerator
15/2
Divide the numbers in the denominator
15/2
The simplified expression is 15/2
That's it. hope it wasn't too hard to understand?
The seventh term of the sequence is
-1
—
25
Answer:
(x²-10x+33)/(-8) = y
Step-by-step explanation:
The distance between any point on a parabola from both its focus and directrix are the same.
Let's say we have a point (x,y) on the parabola. We can then say that using the distance formula,
is the distance between (x,y) and the focus. Similarly, the distance between (x,y) and the directrix is |y-1| (I use absolute value here because distance is always positive). We can find this equation by taking the shortest distance from the point to the line. Because the closest point to the line will be the same x value as the point itself, the distance is simply the distance between the y value of the point and the y value of the directrix.
Equating the two equations given, we have

square both sides to get
(x-5)²+(y+3)²=(y-1)²
expand the y components
(x-5)² + y²+6y+9 = y²-2y+1
subtract y²+6y+9 from both sides
(x-5)² = -8y - 8
expand the x components
x²-10x+25 = -8y - 8
add 8 to both sides to isolate the -8y
x²-10x+33 = -8y
divide both sides by -8 to isolate y
(x²-10x+33)/(-8) = y
Answer:
The point P(1,-3) is not a solution to the system.
Step-by-step explanation:
Given
Let a point be P(1,-3)
Here x = 1 ; y = -3
Substituting the values of x,y in the function

For y<x-1
-3 < 1-1
-3<0 (True)
now for,
y>-x+2
-3 > -1 + 2
-3 > 1 (False)
Hence the point is not a solution to the system.