Note: Consider the side of first triangle is TQ instead of TA.
Given:
Triangles TQM and TPN which share vertex T.
To find:
The theorem which shows that 
.
Solution:
In triangle TQM and TPN,
[Given]
[Given]
[Given]
Since two sides and their including angle are congruent in both triangles, therefore both triangles are congruent by SAS postulate.
[SAS]
Therefore, the correct option is C.
yeah
I understand that I can do you want to go
y=-3x+4
this is a line with slope -3 and y intercept of 4
the line is all the points that are the solutions to the equation
D.a line that shows the set of all solutions to the equation
Answer:
Lies in the shaded regions of both the top and bottom inequalities.
Step-by-step explanation:
The point of solution for BOTH systems of inequalities must work for both equations. Therefore, the point has to lie in both top and bottom shaded regions or it won't work for both, but just one.
