Try C if it doesn’t work try A,B,D
Answer:
Ratio 2:3 I think :)
Step-by-step explanation:
The answer is 12/12/4 total length or if you turn it into a mixed number it will be 3/0/4 witch is 3 whole. hoped this helped you :)
Answer:
a. x = 40 wpm
b. MOE = 4.4 wpm.
c. If you were to create many more confidence intervals from many different random samples, you would expect 95% all of the confidence intervals to have centers and widths that include the true mean.
d. About 5% of the confidence intervals would not capture the parameter (true mean) you are trying to estimate.
Step-by-step explanation:
We have a 95% confidence interval for the mean with bounds 35.6 and 44.4.
This is estimated from a sample that, in this case, has a sample size of n=54.
The value of x, used to construct the interval, will be at the center of the interval. Then we can calculate the value of x as the average between the two bounds:
The margin of error is equal to the difference between x and any of the bounds:
c. If you were to create many more confidence intervals from many different random samples, you would expect 95% all of the confidence intervals to have centers and widths that include the true mean.
d. About 5% of the confidence intervals would not capture the parameter (true mean) you are trying to estimate.
Answer:
The number of gallons of 20% alcohol solution is 12 and the number of gallons of 60% alcohol solution is 4
Step-by-step explanation:
Let
x ----> the number of gallons of 20% alcohol solution
y ----> the number of gallons of 60% alcohol solution
we know that
20%=20/100=0.20
60%=60/100=0.60
30%=30/100=0.30
x+y=16
x=16-y ------> equation A
0.20x+0.60y=16(0.30) ------> equation B
Solve by substitution
Substitute equation A in equation B and solve for y
0.20(16-y)+0.60y=16(0.30)
3.2-0.20y+0.60y=4.8
0.40y=4.8-3.2
0.40y=1.6
y=4 gal
Find the value of x
x=16-y
x=16-4=12 gal
therefore
The number of gallons of 20% alcohol solution is 12 and the number of gallons of 60% alcohol solution is 4