The answer is choice A.
In this problem, we are shrinking the poster by 1/4 of its size.
Which means you need to divide the sides by 4
For width:
![w = \frac{32}{4} = 8](https://tex.z-dn.net/?f=w%20%3D%20%20%5Cfrac%7B32%7D%7B4%7D%20%20%3D%208)
For length:
Q. How many triangles can be constructed with sides measuring 5 m, 16 m, and 5 m?
Solution:
Here we are given with the sides of the triangle as 5m, 16m and 5.
As the Triangle inequality we know that
The sum of the length of the two sides should be greater than the length of the third side. But this inequality fails here.
Hence no triangle can be made.
So the correct option is None.
Q.How many triangles can be constructed with sides measuring 6 cm, 2 cm, and 7 cm?
Solution:
Here we are given with the sides of the triangle as 6m, 2m and 7m.
As the Triangle inequality we know that
The sum of the length of the two sides should be greater than the length of the third side. The given values follows the triangle inequality.
Hence one triangle can be formed.
So the correct option is one.
2x^2-7x-4=0
2x^2-8x+x-4=0
2x(x-4)+1(x-4)=0
(2x+1)(x-4)=0
x=-1/2, 4
Answer:
What expressions are equivalent to 20
Step-by-step explanation:
since you didn't .show a link this is my guess, i guess.
4x5=20