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guajiro [1.7K]
3 years ago
5

Please help its a test

Physics
1 answer:
Fudgin [204]3 years ago
5 0

Answer:

option D : covalent bond

Explanation:

option D is the correct answer of this question .

<em>plz </em><em>mark</em><em> my</em><em> answer</em><em> as</em><em> brainlist</em><em>.</em>

<em>hope </em><em>this</em><em> will</em><em> be</em><em> helpful</em><em> to</em><em> you</em><em>.</em>

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A planet is 15 light years from earth. At which of the following speeds will the crew of a spaceship complete the trip to the pl
Svetradugi [14.3K]

Answer:

option c) 0.88c is the correct answer

Explanation:

using the Lorrentz equation we have

t=\frac{d}{v}\sqrt{1-(\frac{v}{c})^2}

where,

t = time taken to cover the distance

d = Distance

v = velocity

c = speed of light

given

d = 15 light years

Now,

8years=\frac{15years\times c}{v}\sqrt{1-(\frac{v}{c})^2}

or

(\frac{v}{c})^2\times (\frac{8}{15})^2=1-(\frac{v}{c})^2

or

(\frac{v}{c})^2\times 0.284=1-(\frac{v}{c})^2

or

(\frac{v}{c})^2\times 0.284 + (\frac{v}{c})^2 =1

or

(1.284\times \frac{v}{c})^2 =1

or

(\frac{v}{c}) =\sqrt{\frac{1}{0.284}}

or

v=0.88c

7 0
3 years ago
Two rockets are fired at each other with initial velocities of 150m/s150m/s and are 6000m6000m apart. The first rocket is accele
Nataliya [291]

Answer:

3469.788 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

First rocket

s=ut+\frac{1}{2}at^2\\\Rightarrow s=150\times t+\frac{1}{2}\times 5\times t^2\\\Rightarrow s=150t+2.5t^2\ m

Second rocket

s=ut+\frac{1}{2}at^2\\\Rightarrow s=150\times t+\frac{1}{2}\times 15\times t^2\\\Rightarrow s=150t+7.5t^2\ m

When this will collide the total distance they would have covered would be 6000 m.

6000=150t+2.5t^2+150t+7.5t^2\\\Rightarrow 6000=300t+10t^2\\\Rightarrow 10t^2+300t-6000=0

t=5\left(\sqrt{33}-3\right),\:t=-5\left(3+\sqrt{33}\right)\\\Rightarrow t=13.72, -43.72

Hence at 13.72 seconds they will collide assuming they are launched at the same time.

s=150t+7.5t^2\\\Rightarrow s=150\times 13.72+7.5\times 13.72^2\\\Rightarrow s=3469.788\ m

The second rocket would have gone 3469.788 m when they collide

7 0
4 years ago
The feeling of weightlessness occurs because _____________________.
lbvjy [14]

Answer:

The feeling of weight is one of compression.

Explanation:

All your body is being pulled down by gravity yet your feet ( if standing) or your back or something is holding you up.  

Your body is compressed by the PAIR of forces and it is that compression that you feel.  

So when you remove the supporting force then all the body is free to move together and there is no compression within you.  

Hence you perceive no weight.

8 0
3 years ago
Read 2 more answers
A skydiver has jumped out of a plane and is falling faster and faster. What forces are present in this situation?
Rainbow [258]
Its C bc i had the same one and gotta right
4 0
4 years ago
Read 2 more answers
A sprinter accelerates from rest to 10.0 m/s in 1.28 s . Part A Part complete What is her acceleration in m/s2? a a = 7.81 m/s2
Mashutka [201]

Explanation:

It is given that,

Initial speed of sprinter, u = 0

Final speed of sprinter, v = 10 m/s

Time taken, t = 1.28 s

a. We need to find the acceleration of sprinter. It can be calculated using first equation of motion as :

a=\dfrac{v-u}{t}

a=\dfrac{10\ m/s}{1.28\ s}

a=7.81\ m/s^2

b. Final speed of the sprinter, v = 36 km/h

Time, t = 0.000355 h

Acceleration, a=\dfrac{36}{0.000355}

a=101408.45\ km/h^2

Hence, this is the required solution.

3 0
4 years ago
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