Answer:
![\left[\begin{array}{ccc}(-p)&--->&q\\f&t&t\\f&t&t\\t&t&f\\t&f&f\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%28-p%29%26---%3E%26q%5C%5Cf%26t%26t%5C%5Cf%26t%26t%5C%5Ct%26t%26f%5C%5Ct%26f%26f%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
First, we find all the possibilities for p and q in a table:
p q
t t
t f
f t
f f
then -p:
-p q
f t
f f
t t
t f
and we apply the operator --> (rightarrow), that is only f (false) y if the first one is t (true) and the second one is f (false)
-p ---> q
f t t
f t f
t t t
t f f
Answer:
p=25
Step-by-step explanation:
5p-4(p+3)=13
5p-4p-12=13
x-12=13
x=13+12
x=25
a check:
5(25)-4(25+3)=13
125-100-12=13
125-112=13
13=13
3 - 2x > = -17
-2x > = -17 - 3
-2x > = - 20...change the inequality sign when dividing by a negative
x < = -20/-2
x < = 10.........graph D
Wait let me make it i will be back soon
Answer:
y=0.6x+3
slope of the line 0.6 point (−3,−5)
(y+5)= 0.6(x+3)
