The number of kilometres travelled by the satellite in discuss in which case, the satellite makes 8 revolutions around the earth is; C = 177,271.8 km.
<h3>What is the distance in kilometres covered by the satellite after 8 revolutions?</h3>
Given from the task content, the earth's diameter is; 6371 km and since, the height at which the satellite orbits the earth is; 343km, it follows that the diameter of orbit if the satellite in discuss is;
D = 6371 + (343)×2
Hence, we have; diameter, D = 7057 km.
Hence, the distance travelled after 8 revolutions is;
C = 8 × πd
C = 8 × 3.14 × 7057
C = 177,271.8 km.
Read more on circumference of a circle;
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Answer:
39.5
Step-by-step explanation:
We put the numbers in order least to greatest and pick the middle one because that number is the median:
36, 38, 39, 39, 40, 47, 48, 51
Since 39 and 40 are tied for the median we go in between those two numbers, 39.5. The answer is 39.5.
Answer:
last option
Step-by-step explanation:
imagine a number line
________________________________________________
-3 -2 -1 0 1 2 3
|
-2.34 would be found somewhere over there
The space between the two spheres will be the volume of the larger sphere minus the volume of the smaller sphere. Given that the volume of any sphere is:
V=(4πr^3)/3 The space between to sphere of different radius and positioned about the same center is:
S=(4πR^3)/3-(4πr^3)/3 I used S=volume of space, R=larger radius and r=smaller radius...
S=(4π/3)(R^3-r^3), we are told that R=5 and r=4 so
S=(4π/3)(5^3-4^3)
S=(4π/3)(125-64)
S=(4π/3)(61)
S=244π/61
S=4π cm^3
S≈12.57 cm^3 (to nearest hundredth of a ml)
