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erastovalidia [21]
3 years ago
15

In the function

Mathematics
1 answer:
Gala2k [10]3 years ago
5 0

Answer:

A.  It reflects the graph across the x-axis.

Step-by-step explanation:

See the attachment.  Each vale of y is changed from a positive to the same negative value, resulting in the reflection.

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The graph of y=6-[sqrt(4-3x)] contains which point?
elena-14-01-66 [18.8K]

Given y=6-[sqrt(4-3x)], focus on the sqrt function:  sqrt(4-3x).  Since the input of this function cannot be negative, any x-value used must pass the test 4-3x>0.  This is equivalent to 4>3x, or 3x<4, or x < 4/3.  This eliminates choice E.

Second, if the y value is an integer, then sqrt(4-3x) must be an integer.  

Checking answers A through D:  

A:  sqrt(4-3) = sqrt(1) = 1 (OK)        Then y=6-[sqrt(1)] = 5  (NO)

B:  sqrt(4-0) = 2 (OK)                     Then y=6-2 = 4   (NO)

C:  sqrt(4-0) = 2 (OK)                      Then y=6-2 = 4 (NO)

D:  sqrt(4-15) Not OK; eliminate

Correct answer:  F:  None of the above answers are correct

4 0
4 years ago
If X-A=B what is X???
ale4655 [162]

Answer:

B

Step-by-step explanation:

8 0
3 years ago
What is 7.43 rounded to he nearest hundredth
vazorg [7]
<span>What is 7.43 rounded to he nearest hundredth?

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7.43</span>
4 0
4 years ago
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Svet_ta [14]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
Suppose you have line AB on a coordinate plane located at A(-3,-4) and B(5,-4). Under a dilation centered at (9,0), line AB
masya89 [10]

Answer:

\dfrac{1}{4}

Step-by-step explanation:

Center of dilation: O(9,0).

Line AB with A(-3,-4) and B(5,-4) is dilated with the scale factor k and center of dilation at O to form line A'B' with A'(6,-1) and B'(8,-1).

Then

OB'=kOB\\ \\OA'=kOA

Since

OB'=\sqrt{(8-9)^2+(-1-0)^2}=\sqrt{1+1}=\sqrt{2}\\ \\OB=\sqrt{(5-9)^2+(-4-0)^2}=\sqrt{16+16}=4\sqrt{2},

then

\sqrt{2}=k\cdot 4\sqrt{2}\\ \\k=\dfrac{1}{4}

6 0
3 years ago
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