Answer:
204
Step-by-step explanation:
Square of 14 = 14 × 14 = 196
Cube of 2 = 2 × 2 × 2 = 8
So sum of square of 14 & cube of 2= 196 + 8 = 204
Answer:
x=4
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
3(x+2)=2(x+5)
(3)(x)+(3)(2)=(2)(x)+(2)(5)(Distribute)
3x+6=2x+10
Step 2: Subtract 2x from both sides.
3x+6−2x=2x+10−2x
x+6=10
Step 3: Subtract 6 from both sides.
x+6−6=10−6
x=4
The question is what numbers satisfy A ∩ C.
The symbol ∩ means intersection, .i.e. you need to find the numbers that belong to both sets A and C. Those numbers might belong to the set C or not, because that is not a restriction.
Then lets find the numbers that belong to both sets, A and C.
Set A: perfect squares from A to 100:
1^2 = 1
2^2 = 4
3^2 = 9
4^2 = 16
5^2 = 25
6^2 = 36
7^2 = 49
8^2 = 64
9^2 = 81
10^2 = 100
=> A = {1, 4, 9, 16, 25, 36, 49, 64, 81, 100}
Set C: perfect fourths
1^4 = 1
2^4 = 16
3^4 = 81
C = {1, 16, 81?
As you see, all the perfect fourths are perfect squares, so the intersection of A and C is completed included in A. this is:
A ∩ C = C or A ∩ C = 1, 16, 81
On the other hand, the perfect cubes are:
1^3 = 1
2^3 = 8
3^3 = 27
4^3 = 81
B = {1, 8, 27, 81}
That means that the numbers 1 and 81 belong to the three sets, A, B, and C.
In the drawing you must place the number 16 inside the region that represents the intersection of A and C only, and the numbers 1 and 81 inside the intersection of the three sets A, B and C.
Answer:
Hey there!
5. f(4) is 3. f(3) is 2. Thus, f[f(4)]=2
6. g(2) is 3. g(3) is 1. g[g(2)]=1
Hope this helps :)
