Answer:
Proved
Step-by-step explanation:
To prove that every point in the open interval (0,1) is an interior point of S
This we can prove by contradiction method.
Let, if possible c be a point in the interval which is not an interior point.
Then c has a neighbourhood which contains atleast one point not in (0,1)
Let d be the point which is in neighbourhood of c but not in S(0,1)
Then the points between c and d would be either in (0,1) or not in (0,1)
If out of all points say d1,d2..... we find that dn is a point which is in (0,1) and dn+1 is not in (0,1) however large n is.
Then we find that dn is a boundary point of S
But since S is an open interval there is no boundary point hence we get a contradiction. Our assumption was wrong.
Every point of S=(0, 1) is an interior point of S.
Evaluate question answers
1. 6x7 -3
V
42 - 3
V
39
Answer
39
2. 2x6+3x7 - (-3)
V
12 + 21 - (-3)
V
12 + 21 + 3
V
36
Answer
36
3. 5 x (-3) +7 - 6
V
-5 x3+7 - 6
V
-15 + 7- 6
V
-14
Find the sum or difference answers
1. Simplify or expand
(16m 4 - 8m + 3) + (-7m4 - m2 - 8)
16m4 - 8m + 3 - 7m4 - m2 - 8
V
9m4 - 8m - 5 - m2
V
9m 4 - m2 - 8m - 5
Answer
9m 4 - m2 - 8m - 5
2. Simplify or expand
(3x2 - 5x + 9) + (2x2 + 9x -4)+ (7x- 11)
v
3x2 - 5x + 9+ 2x2+9x - 4+7x-11
V
5x2 + 11x - 6
Answer
5x2 + 11x - 6
3. Simplify or expand
(3y2 - y - 6) - (42 + 5y+ 3)
V
3y2 - y - 6 - 4y2 - 5y - 3
V
-y2 - 6y - 9
Answer
-y2 - 6y - 9
4. -7 -2+2x2+ 9x
2 Simplify or expand
-7 - 2+2x2+9x
V
-9 + 2x2 + 9x
V
2x2 + 9x - 9
Answer
2x2 + 9x - 9
Answer:
4073.76
Step-by-step explanation:
True.
The y-axis of the f(x) must equal to the x-axis of g(x)
The x-axis of the f(x) must equal to the y-axis of g(x)
Answer:
AM = 6
Step-by-step explanation:
Using the property of a parallelogram
• The diagonals bisect each other
MO is a diagonal, hence
AM = AO = 6
