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2 years ago

I need help with maths please help

Mathematics

2 answers:

Dmitry_Shevchenko [17]2 years ago

8 0

Answer:

a)-2,0,6 b) ,A,B,C

Step-by-step explanation:

solve the x and y axis by using graphical method
because we have been given the values of x we replace them by the values given hence we can say y=-2²+2 which is -2 for the first box in ad then 0in the second and 6 in the third
you come and look in the graph which suits the equation by using the table you completed like -1on the x axis and 1 on the y axis goes for both Curve A and B then 2 on the x axis and 6 on the y axis goes for curveC

german2 years ago

5 0

Answer:(for A). x -2,-1,0,1,2

Y 0, 1,2,3,4

Step-by-step explanation:

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Question number 4 please help

Korvikt [17]

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2 years ago

What is the y-intercept of a line that has a slope of 3 and passes through point (-1, -7)?

xxTIMURxx [149]

Answer:

-4

Step-by-step explanation:

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3 years ago

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The numbers 7, 11, 12, 13, 14, 18, 21, 23, 27, and 29 are written on separate cards, and the cards are placed on a table with th

kaheart [24]

Answer:

3/10

Step-by-step explanation:

Step 1 : Write the formula of calculating probability

Probability = Number of favourable outcomes/Number of total outcomes

Step 2 : Identify the favourable (requires) outcomes and the total outcomes

Total outcomes are the total cards that are placed on the table = 10 cards
The favourable outcomes are the number of cards that have an even number on them.

12, 14, 18 = 3 cards

Step 3 : Substitute the values in the formula

Probability = Number of favourable outcomes/Number of total outcomes

Probability = 3/10

Therefore, the probability of picking a card with and even number is 3/10.

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3 years ago

In simplest radical form, what are the solutions to the quadratic equation 6 = x2 – 10x?

vichka [17]

Answer:

$x = 5+\sqrt{31}\,\, and\,\, x=5-\sqrt{31}$

Step-by-step explanation:

We need to solve the quadratic equation

6 = x^2 -10x

Rearranging we get,

x^2-10x-6=0

Using quadratic formula to solve the quadratic equation

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

a= 1, b =-10 and c=6

Putting values in the quadratic formula

$x=\frac{-(-10)\pm\sqrt{(-10)^2-4(1)(-6)}}{2(1)}\\x=\frac{10\pm\sqrt{100+24}}{2}\\x=\frac{10\pm\sqrt{124}}{2}\\x=\frac{10\pm\sqrt{2*2*31}}{2}\\x=\frac{10\pm\sqrt{2^2*31}}{2}\\x=\frac{10\pm2\sqrt{31}}{2}\\x = 5\pm\sqrt{31}$

So, $x=5+\sqrt{31}\,\, and\,\, x=5-\sqrt{31}$

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3 years ago

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X-y=3 slope intercept

LekaFEV [45]

Slope intercept is x=3, y=-3. Hope this helped!

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