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2 years ago

Simplify the expression 5a – 2b – 3 + 2b – 6a A. –4 B. 2a – 4b C. –a – 3 D. a – 3

Mathematics

1 answer:

ad-work [718]2 years ago

8 0

Answer:

C. -a-3

Step-by-step explanation:

Group like terms:

5a and -6a

-2b and +2b

-3

5a - 6a equals -a (-1a, but you don't write the 1)

-2b and + 2b = 0

Now you have -a and -3.

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How many years is 694.44 days?

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Answer:

1.9 years

Step-by-step explanation:

There are 365 days in a year

694.44 / 365 = 1.9

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Which expression is a possible leading term for the polynomial function graphed below?

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Answer:

D, 22x^9

Step-by-step explanation:

Here's a key for end behavior: Look at the leading term

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2 years ago

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Devon is 13 years old. this is 4 years younger than his older brother, Todd. Write and solve a subtraction equation to find Todd

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Answer:

9 yrs old

Step-by-step explanation:

13-4=9

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3 years ago

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What is the variance of 5, 13, 32, 37, 49, 51, 63

kramer

Answer:

s2 ≈ 438.2383

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3 years ago

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A consumer products company found that 44% of successful products also received favorable results from test market research, w

Korolek [52]

Answer:

0.80
0.289
0.20
0.711

Step-by-step explanation:

Given:

$P(S\cap F)=0.44\\P(S\cap F^{c})=0.13\\P(S^{c}\cap F^{c}) = 0.32\\P(S^{c}\cap F) = 0.11$

The rule of total probability states that:

$P(A) = P(A\cap B) + P(A\cap B^{c})$

Compute the individual probabilities as follows:

$P(S) = P(S\cap F) + P(S\cap F^{c})\\=0.44+0.13\\0.57$

$P(S^{c}) = 1 - P(S)\\=1-0.57\\=0.43$

$P(F) = P(S\cap F) + P(S^{c}\cap F)\\=0.44+0.11\\=0.55$

$P(F^{c})=1-P(F)\\=1-0.55\\=0.45$

Conditional probability of an event A given B is:

$P(A|B)=\frac{P(A\cap B)}{P(B)}$

Compute the value of $P(S|F)$ :

$P(S|F)=\frac{P(S\cap F)}{P(F)}\\=\frac{0.44}{0.55}\\=0.80$

Compute the value of $P(S|F^{c})$

$P(S|F^{c})=\frac{P(S\cap F^{c})}{P(F^{c})}\\=\frac{0.13}{0.45}\\=0.289$

Compute the value of $P(S^{c}|F)$

$P(S^{c}|F)=\frac{P(S^{c}\cap F)}{P(F}\\=\frac{0.11}{0.55}\\=0.20$

Compute the value of $P(S^{c}|F^{c})$

$P(S^{c}|F^{c})=\frac{P(S^{c}\cap F^{c})}{P(F^{c})}\\=\frac{0.32}{0.45}\\=0.711$

3 0

3 years ago