Answer with Explanation:
Total number of members in School Club = 80 members
Number of member randomly Selected,that is sample size used (P) = 50 members
Number of members who are planning to vote for Talia = 38 members
Z Score for 95% confidence interval =1.96
it is given that Margin of Error ,E,of the poll using a 95% confidence interval=12%
Standard Deviation=4.3 (approx)
→95% confidence level for students who are planning to vote for Talia as president of the club lie between → 38 + 4.3 = 42.3 to 38 -4.3=33.7.
→So, members which will vote for Talia as president of the club lies between minimum of 33 members and maximum of 42 members.
Answer:
The p -value is less than 0.001.
Step-by-step explanation:
Given information:
Sample size = 25 chips
Sample mean = 985
Sample standard deviation = 10
Let as assume that sample is distributed normally.
The formula for test statistic
where,
is sample mean
μ is population mean.
s is sample standard deviation.
n is sample size.
The value of test statistic is
The p-value is
Therefore the p -value is less than 0.001.
Answer: 0.238853503185
(I obviously used a calculator.)
If you rounded this answer, it would be 0.24. Hope this helps!
Answer:
x = 2
y = -3
Step-by-step explanation:
The given equation is,
22(x + yi) + (28 + 4i) = 72 - 62i
By solving this equation further,
22x + 22yi + 28 + 4i = 72 - 62i
(22x + 28) + (22y + 4)i = 72 - 62i
Now both the sides of the equation is in the form of complex number,
By comparing real and imaginary parts given on both the sides,
22x + 28 = 72
22x = 72 - 28
22x = 44
x = 2
22y + 4 = -62
22y = -62 - 4
22y = -66
y = -3
Therefore, x = 2 and y = -3 are the values for which the given equation is true.
hey what's up! the answer is c
