Let the number of bags that he would have been used to put 3 kg of apples be x. Thus the number of bags that would be used to put 2kgs will therefore be (x+9), hence the total number of kgs the bags will hold will be given by:
3*x=3x kgs
2(x+9)=(2x+18) kgs
since the total weights are the same then:
2x+18=3x
hence
18=3x-2x
18=x
thus the number of bags required to put 3 kgs of apples will be 18. Thus the total Kgs of apples was:
3x
=3*18
=54 kgs
Answer:
10=10
Step-by-step explanation:
y-3x+15=10
y=3x-15+10
y=3x-5
subtitute y=3x-5 in the above equation:
3x-5-3x+15=10 (3x will be eliminated with -3x)
-5+15=10
10=10
(i hope this is the way you want the answer but at least I think it is correct)
Answer:
c(X)=R(X)
125x+18000=215x
18000=215x-125x
18000=90x (divede both sides by 90)
X=200
The first one is independent, and the second one is dependent.
Answer:
−35.713332 ; 0.313332
Step-by-step explanation:
Given that:
Sample size, n1 = 11
Sample mean, x1 = 79
Standard deviation, s1 = 18.25
Sample size, n2 = 18
Sample mean, x2 = 96.70
Standard deviation, s2 = 20.25
df = n1 + n2 - 2 ; 11 + 18 - 2 = 27
Tcritical = T0.01, 27 = 2.473
S = sqrt[(s1²/n1) + (s2²/n2)]
S = sqrt[(18.25^2 / 11) + (20.25^2 / 18)]
S = 7.284
(μ1 - μ2) = (x1 - x2) ± Tcritical * S
(μ1 - μ2) = (79 - 96.70) ± 2.473*7.284
(μ1 - μ2) = - 17.7 ± 18.013332
-17.7 - 18.013332 ; - 17.7 + 18.013332
−35.713332 ; 0.313332
