So subtract 55 from 35
35 - 55 = -20
then, put -20 over 55
-20/55 equals -0.36 repeating, rounded to -0.36, which equals 36%
the negative stands for decrease, so it's around 36% decrease
If you flipped the graph y=x^2+2x-2 vertically, you would get the graph y=-(x^2+2x-2) this is True.
An isotherm on a geographic map is a type of
equal temperature at a given date or time. And if we talk about thermodynamics,
it is a curve on a Pressure – Volume diagram at a constant temperature.
Basing from the graph, we can actually see that
the interval is:
10 <span>Fahrenheit degrees</span>
Answer:
Area of trapezium = 4.4132 R²
Step-by-step explanation:
Given, MNPK is a trapezoid
MN = PK and ∠NMK = 65°
OT = R.
⇒ ∠PKM = 65° and also ∠MNP = ∠KPN = x (say).
Now, sum of interior angles in a quadrilateral of 4 sides = 360°.
⇒ x + x + 65° + 65° = 360°
⇒ x = 115°.
Here, NS is a tangent to the circle and ∠NSO = 90°
consider triangle NOS;
line joining O and N bisects the angle ∠MNP
⇒ ∠ONS =
= 57.5°
Now, tan(57.5°) = 
⇒ 1.5697 = 
⇒ SN = 0.637 R
⇒ NP = 2×SN = 2× 0.637 R = 1.274 R
Now, draw a line parallel to ST from N to line MK
let the intersection point be Q.
⇒ NQ = 2R
Consider triangle NQM,
tan(∠NMQ) = 
⇒ tan65° =
⇒ QM =
QM = 0.9326 R .
⇒ MT = MQ + QT
= 0.9326 R + 0.637 R (as QT = SN)
⇒ MT = 1.5696 R
⇒ MK = 2×MT = 2×1.5696 R = 3.1392 R
Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).
⇒ A = (
) × (ST)
= (
) × 2 R
= 4.4132 R²
⇒ Area of trapezium = 4.4132 R²
Answer:
y = - 5/2x - 23/2
Step-by-step explanation:
b = y - (slope)(x)
b = -4 - (-5/2)(-3)
b = -4 - 15/2 = - 23/2
y = -5/2x - 23/2