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3 years ago

Recipe uses 3 cups of flour 2 cups of sugar divide the first quantity by the second quantity defined the related rate

1 answer:

4 0

What the question is stating is that you need to divide 3 by 2 ....3 divided by 2 is 1.5 ...That is the answer to your question!

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Suppose corn chips cost 28.5 cents per ounce. If a bag costs $3.75, how many ounces are in the bag of chips? Round to the neares

ki77a [65]

13.16oz are in the bag because $3.75÷$0.285 is 13.16oz

7 0

3 years ago

Read 2 more answers

827 divided by 1120

KiRa [710]

It can be the last one, 827 over 1120

Hope that helps

4 0

3 years ago

Read 2 more answers

Kameryn types 75 words per minute and is just starting to write a term paper. Joe already has 510 words written and types at a s

AnnZ [28]

Answer:

Kameryn will have more words typed than Joe when the number of minutes exceeds 34.

Step-by-step explanation:

Let

x -----> the number of minutes

y ----> the total words typed

we know that

<em>Kameryn</em>

$y=75x$ -----> equation A

$y=60x+510$ -----> equation B

Solve the system of equations by substitution

Substitute equation A in equation B and solve for x

$75x=60x+510$

$75x-60x=510$

$15x=510$

$x=34\ minutes$

That means

For x=34 minutes

The amount of words written by Kameryn and Joe are the same.

therefore

For x > 34 minutes

Kameryn will have more words typed than Joe when the number of minutes exceeds 34.

6 0

3 years ago

Which expressions are polynomials?

Katarina [22]

I-1 is the polynomials because I is the linear term and 1 is the constant

4 0

2 years ago

Evaluate the given integral by making an appropriate change of variables. 10 x ? 5y 8x ? y da, r where r is the parallelogram en

Artyom0805 [142]

Take

$\begin{cases}u=x-5y\\v=8x-y\end{cases}$

so that you have

$\begin{cases}\mathbf x(u,v)=\dfrac{-u+5v}{39}\\\\\mathbf y(u,v)=\dfrac{-8u+v}{39}\end{cases}$

which gives a Jacobian determinant of

$|\det J|=\left|\begin{vmatrix}\mathbf x_u&\mathbf x_v\\\mathbf y_u&\mathbf y_v\end{vmatrix}\right|=\dfrac1{32}$

So upon transforming the coordinates to the u-v plane, you have (and I'm guessing on what the integrand actually is)

$\displaystyle\iint_R(10x-5y)(8x-y)\,\mathrm dA=\frac1{32}\int_{u=0}^{u=2}\int_{v=5}^{v=10}\frac5{13}(2u+3v)v\,\mathrm dv\,\mathrm du$
$=\displaystyle\frac5{416}\int_{u=0}^{u=2}\int_{v=5}^{v=10}(2uv+3v^2)\,\mathrm dv\,\mathrm du=\dfrac{2375}{104}$

4 0

3 years ago