6, solution is not extraneous.
Answer:
B. One solution
Step-by-step explanation:
Here are a system of how two equations can be classified ;
• If the gradients are the same but the y-intercepts are different, the system has no solution.
• If the gradients are different, the system has one solution.
• If the gradients are the same and the y-intercepts are the same, the system has infinitely many solutions.
Y= (x/4) + 3
When x =1
y= 13/4
When x=3
y= 15/4
Gradient of Y= (x/4) + 3
=∆y/∆x
= (15/4 - 13/4)/ ( 3-1)
=( 2/4)÷ 2
=( 2/4 ) × (1/2)
= 1/4
-4x + y = 4
When x= 1
Y= 8
When x=3
Y=16
Gradient of -4x + y = 4
=∆y/∆x
= (16 - 8)/(3-1)= 8/2 = 4
Since the gradients are different then the system has one solution.
-19 is the answer
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Answer:
thanks for help
Step-by-step explanation:
this is the expression: 2x - 1 = x. in this scenario, x = 1
