Find the length of a rectangle lot with a perimeter of 66 feet if the length is 3 times more than 4 times the width.
1 answer:
Answer:
27 feet
Step-by-step explanation:
We are told in the question that a lot is rectangular in shape
The perimeter of a rectangle
= 2(L + W)
= 2L + 2W
Where
L = Length of the rectangle
W = Width of the rectangle
From the question,
P = 66 feet
The length is 3 times more than 4 times the width
L = 3 + (4 × W)
= 3+ (4W) = 3 + 4W
Hence,
P = 2L + 2W
66 = 2(3 + 4W) + 2W
66 = 6 + 8W + 2W
Collect like terms
66 - 6 = 8W + 2W
60 = 10 W
W = 60/10
W = 6
The Width of the rectangular lot = 6 feet
To find the length
Perimeter = 2L + 2W
Perimeter - 2W = 2L
L = Perimeter - 2W/2
L = 66 - 2(6)/2
L = 66 - 12/2
L = 54/2
L = 27
Therefore the Length of the rectangular lot = 27 feet
You might be interested in
Answer:
He and each of his sisters will recieve 1/4 of the pizza
Step-by-step explanation:
X = -5 is the answer I believe
Answer:
8x² + 3x - 8
Step-by-step explanation:
(f + g)(x) = f(x) + g(x)
f(x) + g(x) = 6x² + 3x + 1 + 2x² - 9 = 8x² + 3x - 8
Answer:
yyyyyy mccullough krishna tiana's shall j will all pepper wood woo doritos you so
Step-by-step explanation:
guess reddit usually tired discord should takeoff
Answer:
The answer would be c) (5,1/2)!
Hope this helps!
Brainliest?
