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BlackZzzverrR [31]
3 years ago
11

Students were asked to design a lab that would illustrate a concept that

Physics
1 answer:
g100num [7]3 years ago
6 0

Answer:

<em>I</em><em> </em>think that the answer would be D.Given the diagram if you just see you will find that a lamp is projected in such a way that its light falls on the ice cubes so the ice would get a large magnitude of heat energy so the kinetic energy of the molecules increases and at a constant temperature(0°c) they would melt and gets transformed into tiny water doplets as we know if the light is continuous enabled on water droplets then at a certain time it would change into water vapours as we know that if any liquid gets evaporated up then it will only evaporate when it absorbs heat from its surrounding as doing so the surrounding along with glass box would get cool down and so the water vapours on air would also cool down and get condensed on outer glass box particles and if the glass box is porous in nature then the water droplets would fill the box

Hope it helps

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Suppose you want to use this human engine to lift a 2.35 kg box from the floor to a tabletop 1.30 m above the floor. How much mu
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Answer:

The increase in the gravitational potential energy is 29.93 joules.

Explanation:

Given that,

Mass of the box, m = 2.35 kg

It is lifted from the floor to a tabletop 1.30 m above the floor, h = 1.3 m

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The head of a grass string trimmer has 100 g of cord wound in a light, cylindrical spool with inside diameter 3.00 cm and outsid
faust18 [17]

Answer:

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Explanation:

Using Inertia and tangential velocity

a).

w=2250*2\pi *\frac{1}{60}\\ w=235.61

I=\frac{1}{2}*m*((\frac{d_{i} }{2})^{2} +(\frac{d_{e} }{2})^{2})\\m=100g *\frac{ikg}{1000g}=0.1kg\\ d_{i}=3cm*\frac{1m}{100cm}=0.03m \\ d_{e}=18cm*\frac{1m}{100cm}=0.18m\\I=\frac{1}{2}*0.1kg*((\frac{0.03m}{2})^{2} +(\frac{0.18m}{2})^{2})\\I=0.41625x10^{-3}kg*m^{2}

Now using Inertia an w

E=\frac{1}{2}*I*(w)^{2} \\ E=\frac{1}{2}*0.416x10^{-3}*(235.61)^{2} \\E=11.54J

average power=\frac{11.4J}{0.230s}=50.2 W

b).

power=t*w

P=11.5465*0.25*235.61

P=2.957 kW

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