0.23 mm far apart are the second-order fringes for these two wavelengths on a screen 1.5 m away.
<h3>Given wavelengths 710nm and 660nm,0.65mm apart two slits, and a screen 1.5m away.</h3>
Position of n the order fringe = n λ D / d
for n = 2
position = 2 λ D / d
λ = 710 nm , D = 1.5m
d = .65 x 10⁻³
position 1 = 2 x 710 x 10⁻⁹ x 1.5 / .65 x 10⁻³
= 3276.92 x 10⁻⁶ m
= 3.276x 10⁻³ m
= 3.276mm .
For λ = 660 nm
position = 2 λ D / d
λ = 660 nm , D = 1.5 m
d = .65 x 10⁻³
position 2 = 2 x 660 x 10⁻⁹ x 1.5 / .65 x 10⁻³
= 3046.15 x 10⁻⁶ m
= 3.046 x 10⁻³ m
= 3.046 mm .
Difference between their position
= 3.276mm ₋ 3.046 mm
= 0.23 mm .
To know more about Fringes refer to: brainly.com/question/15649748
#SPJ4
Answer
given,
focal length of lens A = 5.77 cm
focal length of lens B= 27.9 cm
flies distance from mirror = 11.3 m
now,
Using lens formula
q =11.79 cm
image of lens A is object of lens B
distance of lens = 59.9 - 11.79 = 48.11
now, Again applying lens formula
q' =66.41 cm
hence, the image distance from the second lens is equal to q' =66.41 cm
Its c after the meteorite hit earth it created a different environment worldwide that animals weren't able to adapt to due to its harsh conditions
The answer is C voltmeter
