The acids react with base and the reaction is known as neutralization
One mole of hydronium ion reacts with one mole of hydroxide ion
Here
a) HI is a monoprotic acid : one mole of HI will give one mole of hydronium ion
b) CsOH is a monohydroxide base : one mole of CsOH will give one mole of hydroxide ion
So one mole of HI will react with one mole of CsOH
The moles of CsOH taken will be calculated from molarity and volume as
Thus moles of CsOH are
moles of HI required is 0.005425 mol
volume of HI required will be
Volume of HI required is 9.86 mL
Answer is:
1: Kr.
2: Cl₂.
3: F₂.
4: O₂.
5: N₂.
6: He.
The lighter (smaller) particles move more quickly than heavier (larger) ones at the same temperature.
Calculate molar masses of the compounds:
M(Cl₂) = 70.9 g/mol; molar mass of chlorine gas.
M(F₂) = 38 g/mol, molar mass of fluorine gas.
M(He) = 4.002 g/mol; molar mass of helium.
M(Kr) = 83.8 g/mol; molar mass of krypton.
M(N₂) = 28.01 g/mol; molar mass of nitrogen gas.
M(O₂) = 32 g/mol; molar mass of oxygen gas.
Answer:
Explanation:
Given: Entropy of surrounding: ΔSsurr = ?
Temperature: T= 355 K
The change in enthalpy of reaction: ΔH = -114 kJ
Pressure: P = constant
As we know, ΔH = -114 kJ ⇒ negative
Therefore, the given reaction is an exothermic reaction
Therefore, Entropy of surrounding at <em>constant pressure</em> is given by,
<u><em>In the given reaction:</em></u>
2NO(g) + O₂(g) → 2NO₂(g)
As, the number of moles of gaseous products is less than the number of moles of gaseous reactants.
As we know, <em>for a spontaneous process, that the total entropy should be positive.</em>
<u>Therefore, at the given temperature,</u>
- if then the given reaction is spontaneous
- if then the given reaction is non-spontaneous
I think it’s going to be 8, which is my best guess. Good luck
The symbol for dinitrogen trisulfide is N2S3