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2 years ago

A gas bubble has a volume of 0.650 mL at the bottom of a lake, where the pressure is

Chemistry

1 answer:

astraxan [27]2 years ago

4 0

Considering the Boyle's law, as the pressure decreases, volume increases and has a value of 2.246 mL.

<h3>Boyle's law</h3>

Boyle's law establishes the relationship between the pressure and the volume of a gas when the temperature is constant.

This law says that the volume occupied by a given mass of gas at constant temperature is inversely proportional to the pressure. This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

P×V=k

If an initial state 1 and a final state 2 are analyzed, Boyle's law is expressed as:

P1×V1=P2×V2

<h3>Volume at the surface of the lake</h3>

In this case, you know:

P1= 3.46 atm
V1= 0.650 mL
P2= 1 atm
V2= ?

Replacing in Boyle's law:

3.46 atm× 0.650 mL= 1 atm×V2

Solving:

V2= (3.46 atm× 0.650 mL)÷ 1 atm

Finally, as the pressure decreases, volume increases and has a value of 2.246 mL.

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4. Why can't the subscripts be changed in a chemical equation in chemistry

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If you change the subscripts it would change the reactants or products and then you would be solving a different formula, you would change what the chemical is

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2 years ago

What type of central-atom orbital hybridization corresponds to each electron-group arrangement:

galina1969 [7]

Tetrahedral arrangement is resulted upon mixing one s and three p atomic orbitals, resulting in 4 hybridized $sp^3$ orbitals → $sp^3$ hybridization.

<h3>What is orbital hybridization?</h3>

In the context of valence bond theory, orbital hybridization (or hybridisation) refers to the idea of combining atomic orbitals to create new hybrid orbitals (with energies, forms, etc., distinct from the component atomic orbitals) suited for the pairing of electrons to form chemical bonds.

For instance, the valence-shell s orbital joins with three valence-shell p orbitals to generate four equivalent sp3 mixes that are arranged in a tetrahedral configuration around the carbon atom to connect to four distinct atoms.

Hybrid orbitals are symmetrically arranged in space and are helpful in the explanation of molecular geometry and atomic bonding characteristics. Usually, atomic orbitals with similar energies are combined to form hybrid orbitals.

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1 year ago

What word or two-word phrase best describes the shape of the nitrite ( NO2- ) ion?

Olin [163]

I think the answer would be nitrogen

6 0

3 years ago

Read 2 more answers

Help me please!

liq [111]

Answer:

Explanation:

Q 1:

Summarize the physical and chemical properties of Uranium.

Physical properties:

Uranium is member of Actinide series.

Its atomic number is 92.

Its atomic mass is 238.0289 amu.

Its density is 18.95 g/cm³.

Its melting point is 1132 °C.

Its boiling point is 3818 °C.

Its vanderwaal radius is 0.121 nm.

It has eleven isotopes.

It is malleable and ductile.

Chemical properties:

It is used as primary material for the production of transuranium elements.

With oxygen it form oxides such as UO , U₂O₅, UO₃, UO₂, UO₄.2H₂ but most common form as U₃O₈ and UO₂.

It also form carbonates with oxidation state of VI.

It form halides with halogens. For example UO₂ react with HF and form UF₄.

UO₂ + 4HF → UF₄ + 2H₂O

It is used in bomb.

The first bomb made up of uranium was contained U-235. It start chain reaction and many uranium atom undergoes fission and produce large amount of energy.

The fertilizer such as phosphate contain large amount of uranium.

It is used in the production of steels and also in lamp.

Uranium-233 also used as nuclear fuel.

Q 2:

In the lesson, many models were used to depict the atom. How does models help you understand atomic structure?

Rutherford atomic model:

Atom consist of positive charges and most of the mass of an atom is concentrated in small region called nucleus but at that time Rutherford not aware of composition of this small region i.e, neutron and proton.

He stated that there are negatively charged particles revolve around the nucleus with a high speed.

Atom is neutral because it consist of negative charged electrons and positive nucleus equal in magnitude and there are strong electrostatic static forced between them.

The size of atom is greater than its nucleus.

Rutherford atomic model did not explain the stability of atom and also the arrangement of electrons in orbits.

Than in 1913 Bohr proposed that electrons are revolved in stable around the nucleus. He suggested that electron's angular momentum is quantized and due to this quantization orbits have fixed energies and electron remain in its orbit can not jump into other orbit until it gain or lost the energy.

Q 3.

How do protons, neutrons, and electrons differ in terms of their electrical charges and locations within the atom?

The electron is subatomic particle that revolve around outside the nucleus and has negligible mass. It has a negative charge.

Symbol= e-

Mass= 9.10938356×10-31 Kg

It was discovered by j. j. Thomson in 1897 during the study of cathode ray properties.

While neutron and proton are present inside the nucleus. Proton has positive charge while neutron is electrically neutral. Proton is discovered by Rutherford while neutron is discovered by James Chadwick in 1932.

Symbol of proton= P+

Symbol of neutron= n0

Mass of proton=1.672623×10-27 Kg

Mass of neutron=1.674929×10-27 Kg

An atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.

All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other. For example if neutral atom has 6 protons than it must have 6 electrons. The sum of neutrons and protons is the mass number of an atom while the number of protons are number of electrons is the atomic number of an atom.

Q 4:

Describe the four fundamental forces. Which of these forces are involved in chemical bonding?

Answer:

Electromagnetic force

Explanation:

There are four fundamental forces:

Gravity

Weak nuclear force

Strong nuclear force

Electromagnetic force

Gravitational force is too weak that's why can not take part in chemical reaction while strong and weak nuclear forces are just involve in nuclear reaction not chemical reaction.

The only fundamental force which is electromagnetic force is take part in chemical reaction. This force is of different types depending upon the type of bonding. For example:

In covalent bond this type of force is occur between the atoms of almost equal electronegativity.

In ionic bond this force is occur is between positive and negative ions.

7 0

3 years ago

When 3.93 grams of lactic acid, CHoOs(s), are burned in a bomb

aliya0001 [1]

The heat released in the combustion of lactic acid is absorbed by the

calorimeter and in the decomposition of the lactic acid.

ΔH°f of lactic acid is approximately <u>-716.2 kJ</u>

Reasons:

Known parameters are;

Mass of the lactic acid = 3.93 grams

Heat capacity of the bomb calorimeter = 10.80 kJ·K⁻¹

Change in temperature of the calorimeter, ΔT = 5.34 K

ΔHrxn = ΔErxn

ΔH°f of H₂O(l) = -285.8 kJ·mol⁻¹

ΔH°f of CO₂(g) = -393.5 kJ·mol⁻¹

The chemical equation for the reaction is presented as follows;

C₃H₆O₃ + 2O₂ → 3CO₂ + 3H₂O

The heat of the reaction = 10.80 kJ·K⁻¹ × 5.34 K = 57.672 kJ

Molar mass of C₃H₆O₃ = 90.07 g/mol

Number of moles of C₃H₆O₃ = $\dfrac{3.93 \, g}{90.07 \, g/mol}$ = 0.043633 moles

Number of moles of CO₂ produced = 3 × 0.043633 moles = 0.130899 moles

Heat produced = 0.130899 mole × -285.8 kJ·mol⁻¹ = -37.4109342 kJ

Moles of H₂O produced = 0.130899 moles

Heat produced = 0.130899 mole × -393.5 ≈ -51.51 kJ

Therefore, we have;

Heat absorbed by the lactic acid = ΔH°f of H₂O + ΔH°f of CO₂ + Heat absorbed by the calorimeter

Which gives;

Heat absorbed by lactic acid = -37.4109342 kJ - 51.51 kJ + 57.672 kJ ≈ -31.249 kJ

The heat absorbed by the lactic acid ≈ -31.249 kJ

$\Delta H^{\circ}f \ of \ C_3H_6O_3 = \dfrac{-31.249}{0.043633} \approx -716.2$

ΔH°f of C₃H₆O₃ ≈ -716.2 kJ

Heat of formation of lactic acid ≈ <u>-716.2 kJ</u>.

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5 0

2 years ago