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2 years ago

A gas bubble has a volume of 0.650 mL at the bottom of a lake, where the pressure is

Chemistry

1 answer:

astraxan [27]2 years ago

4 0

Considering the Boyle's law, as the pressure decreases, volume increases and has a value of 2.246 mL.

<h3>Boyle's law</h3>

Boyle's law establishes the relationship between the pressure and the volume of a gas when the temperature is constant.

This law says that the volume occupied by a given mass of gas at constant temperature is inversely proportional to the pressure. This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

P×V=k

If an initial state 1 and a final state 2 are analyzed, Boyle's law is expressed as:

P1×V1=P2×V2

<h3>Volume at the surface of the lake</h3>

In this case, you know:

P1= 3.46 atm
V1= 0.650 mL
P2= 1 atm
V2= ?

Replacing in Boyle's law:

3.46 atm× 0.650 mL= 1 atm×V2

Solving:

V2= (3.46 atm× 0.650 mL)÷ 1 atm

Finally, as the pressure decreases, volume increases and has a value of 2.246 mL.

Learn more about Boyle's law:

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3 years ago

A 1.2 L weather balloon on the

makkiz [27]

Answer:

330.95K

Explanation:

V₁ = 1.2L

T₁ = 25°C = (25 + 273.15)K = 298.15K

P₁ = 1.0 atm

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V₂ = 1.8L

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From combined gas equation,

(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂

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3 years ago

Perform the following conversions:

jek_recluse [69]

Answer :

The conversion used for the temperature from Fahrenheit to degree Celsius is:

$^oC=\frac{5}{9}\times (^oF-32)$

The conversion used for the temperature from degree Celsius to Kelvin is:

$K=^oC+273$

(a) $1.06^oF$

$^oC=\frac{5}{9}\times (^oF-32)$

$^oC=\frac{5}{9}\times (1.06^oF-32)$

$^oC=-17.188$

The temperature in degree Celsius is, $-17.188^oC$

$K=^oC+273$

$K=-17.188+273$

$K=255.812$

The temperature in Kelvin is, 255.812 K

(b) $3410^oC$

$^oC=\frac{5}{9}\times (^oF-32)$

$3410^oC=\frac{5}{9}\times (^oF-32)$

$^oF=6106$

The temperature in degree Fahrenheit is, $6106^oF$

$K=^oC+273$

$K=3410+273$

$K=3683$

The temperature in Kelvin is, 3683 K

(c) $6.1\times 10^3K$

$K=^oC+273$

$6.1\times 10^3K=^oC+273$

$^oC=5827$

The temperature in degree Celsius is, $5827^oC$

$^oC=\frac{5}{9}\times (^oF-32)$

$5827^oC=\frac{5}{9}\times (^oF-32)$

$^oF=10456.6$

The temperature in degree Fahrenheit is, $10456.6^oF$

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