1)Straight chain hydrocarbons are named according to the number of carbon atoms: CH4, methane; C2H6 or H3C-CH3, ethane; C3H8 or H3C-CH2-CH3, propane; C4H10 or H3C-CH2- CH2-CH3, butane; C5H12 or CH3CH2CH2CH2CH3, pentane; C6H14 or CH3(CH2)4CH3, hexane; C7H16, heptane; C8H18, octane; C9H20, nonane; C10H22, CH3(CH2)8CH3, ..
Multiply the volume by the density. 1 ml = 1 cm^3
1.11 g/cm^3 * 1 cm^3/mL * 386 mL = 428 g
All your units cancel out except for g which is what you would expect since you want units of mass.
The molecular weight of this gas will be 45 g/mol .
The state equilibrium equation for a fictitious perfect gas is known as the ideal gas law, sometimes known as the generic gas equation. Although it has significant drawbacks, it represents a decent approximation of the activity of many gases under various conditions.
Ideal gas law can be expressed as:
PV =nRT
Calculation of molecular weight by using ideal as law.
Given data:
P = 3 atm
T = 127 °c
Density = 4. 20 grams per liter
PV =nRT
where p is pressure , T is temperature and R is gas constant.
PV = gram / molecular weight RT
Molecular weight = (g/v)( 1/P) RT
Putting the given data in above equation.
Molecular weight =4.20 × 1/ 3× 400 × 0.0831
Molecular weight = 45 g/mol.
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I would suggest you to use this instead.
Just place the known substance for example O2 Oxygen as they are asking you, and see where the diagram takes you.
So the answer would be 2 because you’d look at the coefficients of the balanced equation up there. H2O
I hope that was helpful, if you have more questions please ask!