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Mariulka [41]
3 years ago
7

If f(x) = -8x – 6 and g(x) = x+8, what is (fºg)(-7)? Enter the correct answer.

Mathematics
1 answer:
Semmy [17]3 years ago
6 0

9514 1404 393

Answer:

  -14

Step-by-step explanation:

  (f\circ g)(x)=f(g(x))=f(x+8)=-8(x+8)-6\\\\(f\circ g)(x)=-8x-70\\\\(f\circ g)(-7)=-8(-7)-70=\boxed{-14}

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Gail is a real estate agent. She earns $750 per week and a 3% commission on the value of each house she sells. This week she sol
swat32
She made $8,250 this week. 3% of 250,000 is $7,500, you add her weekly pay of $750 and it gives you your answer. 
8 0
3 years ago
Your task is to build a road joining a ranch to a highway that enables drivers to reach the city in the shortest time. The perpe
lubasha [3.4K]

Answer:

(a)In the attachment

(b)The road of length 35.79 km should be built such that it joins the highway at 19.52km from the perpendicular point P.

Step-by-step explanation:

(a)In the attachment

(b)The distance that enables the driver to reach the city in the shortest time is denoted by the Straight Line RM (from the Ranch to Point M)

First, let us determine length of line RM.

Using Pythagoras theorem

|RM|^{2}=30^2+x^2\\|RM|=\sqrt{30^2+x^2}

The Speed limit on the Road is 60 km/h and 110 km/h on the highway.

Time Taken = Distance/Time

Time taken on the road  =\frac{\sqrt{30^2+x^2}}{60}

Time taken on the highway =\frac{50-x}{110}

Total time taken to travel, T =\frac{\sqrt{30^2+x^2}}{60}+\frac{50-x}{110}

Minimum time taken occurs when the derivative of T equals 0.

T^{'}=\frac{x}{60\sqrt{30^2+x^2}}-\frac{1}{110}\\\frac{x}{60\sqrt{30^2+x^2}}-\frac{1}{110}=0\\\frac{x}{60\sqrt{30^2+x^2}}=\frac{1}{110}\\110x=60\sqrt{30^2+x^2}\\

Square both sides

12100x^2=3600(30^2+x^2)\\12100x^2=3240000+3600x^2\\12100x^2-3600x^2=3240000\\8500x^2=3240000\\x^2=\frac{3240000}{8500} =381.18\\x=\sqrt{381.18} =19.52

The road should be built such that it joins the highway at 19.52km from the point P.

In fact,

|RM|=\sqrt{30^2+19.52^2}=35.79km

4 0
3 years ago
A triangle has sides 12 2/3 inches, 10 1/3 inches, and 5 1/3 inches. What is the perimeter (distance around the edges) of the tr
dimulka [17.4K]

The perimeter of a triangle is the sum of its sides​

Perimeter = 12 2/3 inches + 10 1/3 inches + 5 1/3 inches = 28 1/3 inches​

Answer : 28 1/3 inches​

Hope this helps!​​​​​

​\textit{\textbf{Spymore}}​​​​​​​

6 0
3 years ago
Hi guys sorri another one HEHHE <br> I KINDA NEED THIS ASAP...<br> THANKS YO SOMUCHHH
Ket [755]

Answer:

x = -1

Step-by-step explanation:

in pic

<u><em>(Credits: Symbolab)</em></u>

<u><em></em></u>

<u><em></em></u>

<u><em></em></u>

(Hope this helps can I pls have brainlist (crown)☺️)

6 0
2 years ago
Read 2 more answers
Can anyone help me with this. please​
zvonat [6]

Answer:

Step-by-step explanation:

using pythagoras theorem

a^2+b^2=c^2

7^2+KL^2=25^2

49+KL^2=625

KL^2=625-49

KL=\sqrt{576

KL=24

take M as reference angle

using tan rule

tan M=/opposite/adjacent

tan M=KL/ML

tan M=24/7

5 0
3 years ago
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