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3 years ago

Write the equation of the vertical and horizontal lines through ( - 1,9).

Mathematics

1 answer:

dedylja [7]3 years ago

3 0

Answer:

Step-by-step explanation:

horizontal line: y=9

vertical line: x = -1

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What is the area of a circle whose equation is (x-3)² + (y + 1) ² =81?

kupik [55]

Okay, first, given the equation, we need to find out what the radius of the circle is. Let us state the general equation of a circle:

$\frac{(x-x_{1})^2}{r^2}+ \frac{(y-y_{1})_^2}{r^2}=1$

Where $(x_{1}, y_{1})$ is the centre of the circle. In this case, we don't need to know the centre. Just the radius.

Let us start by converting the equation into standard for, which I typed above. Divide both sides by 81.

$\frac{(x-3)^2}{81}+ \frac{(y+1)^2}{81}=1$

Great! We now know the radius of the circle. It is $\sqrt{81}$ because it is the bottom fraction. Now we know that the radius is 9.

So now lets input this into the area of circle formula:

$A=πr^2$

Now we insert our radius.

$A=9^2π$

$=A=81π$

You can convert that into a decimal if you wish.

Hope this helped!

~Cam943, Moderator

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3 years ago

What is the scale factor of 3

Wittaler [7]

A scale factor of 3 means that the new shape is three times the size of the original. To calculate the Scale Factor, we use the following: You can get the 'big' and 'small' from the corresponding sides on the figures. So just get your # and multiply it by 3

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3 years ago

Can someone solve this?

aleksley [76]

Answer:

Considering the Law of Cosines:

$c^2=a^2+b^2-2ab*cosC$

$a=14mi; b=24mi; c=CA; C=91degrees$

$\cos \left(91^{\circ \:}\right)=-0.01745\dots$

$c^2=14^2+24^2-2(14)(24)*\cos \left(91^{\circ \:}\right)\\c^2=196+576-672*\cos \left(91^{\circ \:}\right)\\c^2=772-672*\cos \left(91^{\circ \:}\right)\\c^2=772-672*(-0.01745)\\c^2=772+11.7264\\c=\sqrt{772+11.7264} \\c=\sqrt{783.7264}\\c=27.99mi$

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3 years ago

Given: AABC, m_ACB=90°,<br> CD 1 AB, m ZACD=60º,<br> BC = 6 cm<br> Find: CD, Area of AABC

just olya [345]

Answer:

Look below

Step-by-step explanation:

Given that CDB is 90 degrees, ACB is 90 degrees, and ACD is 60 degrees, we can determine that DCB = 90-60 = 30 degrees.

This means triangle BCD is a 30-60-90 (angle measures) right triangle

The proportions of the sides (from smallest to largest) is

x:x√3:2x

We are given that BC = 6 cm. This means...

2x=6

x=3

This means DB is 3 cm and CD is 3√3 cm

Using the linear pair theorem, we can find that Angle CDA is 90 degrees. This means ACD is also a 30-60-90 triangle.

x=3√3

x√3=9

2x=6√3

Now we need to find AB

AB = AD + DB

AB = 9 + 3

AB = 12 cm

$Area = \frac{1}{2} bh = \frac{1}{2}(12)(3\sqrt3)=6(3\sqrt3)=18\sqrt3$

8 0

3 years ago

What’s another way to write the equation (40x4)-(32x4)=32

zysi [14]

Answer:

160-128=32

Step-by-step explanation:

distribute what is in the parentheses

7 0

2 years ago