The function, g(x), has a constant rate of change and will increase at a faster rate than the function f(x) for all the values of x.
Given:
g(x) = 5/2 x -3 ..... (1)
f(x) = - 3.5 at x = 0
So, putting the value of x=0 in equation (1) for comparison. We get,
g(x) at x = 0
=> g(x) = 5/2 x (0) - 3
=> g(x) = -3
In this value of x function g(x) is faster than function f(x) having a value equal to -3.5.
Similarly, put x = 1 in equation (1) for comparison. We get,
=> g(x) = 5/2 x (1) - 3
=> g(x) = (5-6)/2
=> g(x) = -1/2
In this value of x function g(x) is faster than function f(x) having a value equal to -1.
Similarly, put x = 2 in equation (1) for comparison. We get,
=> g(x) = 5/2 x (2) - 3
=> g(x) = (5-3)
=> g(x) = 2
In this value of x function g(x) is faster than function f(x) having a value equal to 1.5.
Similarly, put x = 3 in equation (1) for comparison. We get,
=> g(x) = 5/2 x (3) - 3
=> g(x) = (15/2 - 3)
=> g(x) = 7.5 - 3
=> g(x) = 4.5
In this value of x function g(x) is faster than function f(x) having a value equal to 4.
Therefore, for all values of x function g(x) is faster than function f(x).
function f(x).
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