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nataly862011 [7]
2 years ago
13

Disodvontage of Artificial Insemination​

Mathematics
1 answer:
oee [108]2 years ago
6 0

Answer:

Potential risk of wasting expensive semen if corners are cut by breeder/vet. Failure because of poor clinical examinations of the breeding pair. The risk of artificial insemination being used for the wrong reasons. Frozen semen must be stored and thawed properly to maintain viability.

Step-by-step explanation:

hope it helped

can i please have a thanks, a 5 star, and a brainliest please... thank you

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If you multiply a number by 3 and divide by 4 the result is 24. what is the number?
solong [7]
To solve this problem, we are going to set up an equation.  Let the number that we are trying to find be represented by the variable x.  If we plug in the numbers that we know, we get the following equation:

3x/4 = 24

To simplify this equation, we need to multiply both sides by 4, to begin getting the x alone on the left side of the equation.

3x = 96

Finally, we need to divide both sides by 3, to get rid of the coefficient that is being multiplied to x.

x = 32

Therefore, the number that you are trying to find is 32.
4 0
3 years ago
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Emma earns 120 frequent flyer miles for every $40 of merchandise she buys with her credit card. Which of the following equations
Stells [14]
120 divided by 40 = 3

That’s the equation
7 0
3 years ago
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Approximate the value of the square root of 110 to the nearest hundredth
DaniilM [7]

Answer:

10.4900

Step-by-step explanation:

pls make a brainliest

3 0
2 years ago
An industry representative claims that 10 percent of all satellite dish owners subscribe to at least one premium movie channel.
Greeley [361]

Answer: 1) 0.6561    2) 0.0037

Step-by-step explanation:

We use Binomial distribution here , where the probability of getting x success in n trials is given by :-

P(X=x)=^nC_xp^x(1-p)^{n-x}

, where p =Probability of getting success in each trial.

As per given , we have

The probability that any satellite dish owners subscribe to at least one premium movie channel.  : p=0.10

Sample size : n= 4

Let x denotes the number of dish owners in the sample subscribes to at least one premium movie channel.

1) The probability that none of the dish owners in the sample subscribes to at least one premium movie channel = P(X=0)=^4C_0(0.10)^0(1-0.10)^{4}

=(1)(0.90)^4=0.6561

∴ The probability that none of the dish owners in the sample subscribes to at least one premium movie channel is 0.6561.

2) The probability that more than two dish owners in the sample subscribe to at least one premium movie channel.

= P(X>2)=1-P(X\leq2)\\\\=1-[P(X=0)+P(X=1)+P(X=2)]\\\\= 1-[0.6561+^4C_1(0.10)^1(0.90)^{3}+^4C_2(0.10)^2(0.90)^{2}]\\\\=1-[0.6561+(4)(0.0729)+\dfrac{4!}{2!2!}(0.0081)]\\\\=1-[0.6561+0.2916+0.0486]\\\\=1-0.9963=0.0037

∴ The probability that more than two dish owners in the sample subscribe to at least one premium movie channel is 0.0037.

8 0
3 years ago
7is subtracted from the quotient of 48 divided by th<br>e sum of 5 &amp; difference of 11 and 8​
kramer

Answer:

7-48=41

÷

5+11-8

bodmas

5+3=8

41÷8=5.125

5 0
3 years ago
Read 2 more answers
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