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Vesnalui [34]
3 years ago
12

What is 6+6 pls help :)​

Mathematics
1 answer:
Paul [167]3 years ago
6 0

Answer:

its 12 sweety hope this helps

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A 10-foot ladder is leaning against a tree. The bottom of the ladder is 4 feet away from the bottom
Naddik [55]

Answer:

4

Step-by-step explanation:

7 0
4 years ago
A number is multiplied by 20, and that product is added to 5. The sum is equal to the product of 5 and 13.
liubo4ka [24]

Answer:

x = 3

Step-by-step explanation:

First, you will pick the first equation :

(x*20)

Then the next,

(x*20) + 5

Then the last equation,

(x*20) + 5 = 5*13

Then you solve

20x + 5 = 65

20x = 65 - 5

20x = 60

20x/20 = 60/20

x = 3

5 0
3 years ago
Help! I can't seem to answer this. (question in photo)
german
The answer would be 48...

4 0
3 years ago
Which equation is an identity?​
kirza4 [7]

Answer:

Option (3).

Step-by-step explanation:

Option (1).

3(x - 1) = x + 2(x + 1) + 1

3x - 3 = x + 2x + 2 + 1

3x - 3 = 3x + 3 [Not True]

Therefore, this equation is not an identity.

Option (2).

x - 4(x + 1) = -3(x + 1) + 1

x - 4x - 4 = -3x - 3 + 1

-3x - 4 = -3x - 2 [Not true]

Therefore, this equation is not an identity.

Option (3).

2x + 3 = \frac{1}{2}(4x + 2) + 2

2x + 3 = 2x + 1 + 2

2x + 3 = 2x + 3 [True]

Therefore, this equation is an identity.

Option (4).

\frac{1}{2}(6x-3)=3(x+1)-x-2

3x - 1.5 = 3x + 3 - x - 2

3x - 1.5 = 2x + 1 [Not true]

Therefore, this equation is not an identity.

6 0
4 years ago
Read 2 more answers
If x is divided by 5 the remainder is 4. If why is divided by 5 the remainder is 1. What is the remainder when x+y is divided by
Naddik [55]

Answer:

0

Step-by-step explanation:

We are given the following:

\frac{x}{5}=q_1+\frac{4}{5}      (equ. 1)

\frac{y}{5}=q_2+\frac{1}{5}      (equ. 2)

We are asked:

\frac{x+y}{5}=q_3+\frac{r}{5}  (equ. 3) , what is r?

The q_i's represent the quotients you get.

r is the remainder of dividing x+y by 5.

We know that r is a number in {0,1,2,3,4}.

x=5q_1+4 (I got this by multiplying both sides of equ 1. by 5.)

y=5q_2+1 (I got this by multiplying both sides of equ 2. by 5.)

Let's add these equations together:

x+y=(5q_1+5q_2)+(4+1)

Factoring the 5 out for the q_i's part and simplify 4+1 gives:

x+y=5(q_1+q_2)+5

So 5 can't be the remainder of dividing something by 5 but see that we can factor this right hand expression more as:

x+y=5(q_1+q_2+1)

So q_3=q_1+q_2+1 while there is no remainder (the remainder is 0).

Let's do an example if you are not convinced at this point that the remainder will be 0.

So choose x=9 since 9/5 gives a remainder of 4.

And choose y=16 since 16/5 gives a remainder of 1.

x+y=9+16=25 and 25/5 gives a remainder of 0.

8 0
3 years ago
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