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2 years ago

Please help Me Quick

Mathematics

1 answer:

Mrac [35]2 years ago

5 0

Answer:

Step-by-step explanation:

First figure out the equation:

We know this is a linear equation because it appears to have a constant slope

Its y-intercept is where it passes in the y-axis, so it's -8

Furthermore, you should also figure out the slope. Notice that the y value increments by 3 every 1 x-value. Rise/Run is 3/1 = 3. Thus, the slope is 3

So your equation is g(x) = 3x - 8

Now we find our inverse function, which is just swapping the x-y values.

Thus, inverse of g(x) ==> y = 3x - 8 ==> x = 3y - 8 ==> x+8 = 3y ==> $\frac{x+8}{3}$

Plug in 7 for x and you get 5

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Six friends shared 79 trading cards and kept a record of how they did it. What does 13 represent? the answers are- The number of

castortr0y [4]

Answer: The number of trading cards each friend ended up with

Step-by-step explanation:

Given that:

Total Number of trading cards = 79

Number of friends = 6

Number of trading cards each friend got of shared equally :

Total Number of trading cards / number of friends

= 79 / 6

= 13.166

Highest number of cards got by each = 13

Number left : 79 - (13 * 6) = 1

Hence, 13 represents the number of trading cards each friend ended up with

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2 years ago

A researcher wished to compare the average amount of time spent in extracurricular activities by high school students in a subur

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Step-by-step explanation:

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2 years ago

A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) a

sdas [7]

Answer:

$y=-\dfrac{13}{49}x^2$

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

$y=ax^2+bx+c$

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

$-13=a(-7)^2+b(-7)+c$

$49a-7b+c=-13$

(x,y) = (7,-13)

$-13=a(7)^2+b(7)+c$

$49a+7b+c=-13$

(x,y) = (0,0)

$0=a(0)^2+b(7)+c$

$c=0$

so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

$49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13$

$49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13$

we can solve these two equation using the elimination method, by simply adding the two equations

$\quad\quad49a-7b=-13\\+\quad49a+7b=-13$

------------------------------

$\quad\quad 98a=-26$

$\quad\quad a=-\dfrac{13}{49}$

Now we can plug this value of a in any of the two equations.

$49a-7b=-13$

$49\left(-\dfrac{13}{49}\right)-7b=-13$

$-13-7b=-13$

$-7b=0$

$b=0$

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

$y=\left(-\dfrac{13}{49}\right)x^2+0x+0$

$y=-\dfrac{13}{49}x^2$

$49y=-13x^2$

This our equation of the arch!

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jenyasd209 [6]

Answer:

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2 years ago