All categories

3 years ago

A stock loses half its value each week. If the stock started at $125, what is it worth after 4 weeks?

Mathematics

1 answer:

Tcecarenko [31]3 years ago

3 0

Answer: 7.81

The formula is

y = 125* (1/2)^4

y = 125 / 16

y = 7.81

So at the end of the 4th week, the stock is worth only 7.81 dollars.

If that is not the motive and the first week doesn't count then the formula changes to...

y = 125 * (1/2)^(n-1)

y = 125 * (1/2)^3

y = 15.625 could be the other answer if you looked at it in that perspective

However, I would go with 7.81 as the answer.

Hope I helped :)

You might be interested in

Find the volume please

Mashutka [201]

Answer:

Volume = 4/3 πr³

V = 4/3*22.7*8

V = 32.656 m³

8 0

3 years ago

Linear equation 1/2X+Y=6

krek1111 [17]

You can graph it but cant answer it because there is two variables so try and change it to slope intercept form do you know how ???????

5 0

4 years ago

Brianna rolls a number cube that has sides labeled 1 to 6 and flips a coin. Write the list of possible outcomes.

Gemiola [76]

The sample space is {(1,H), (1,T), (2,H), (2,T), (3,H), (3,T), (4,H), (4,T), (5,H), (5,T), (6,H), (6,T)}

On the number cube, she could roll any of the numbers from 1 to 6. On the coin, she could flip heads or tails.

5 0

4 years ago

A symbol CAN’T be used to represent

liubo4ka [24]

Step-by-step explanation:

A symbol CAN’T be used to represent

two different values in the same equation

at the same time. true or false

True.

4 0

3 years ago

Jan and Wayne went to the store to buy some groceries. Jan bought 2 cans of corn beef hash and 3 cans of creamed chipped beef fo

yulyashka [42]

Answer:

The system of equations that models the problem is:

$\left \{ {{2*H+3*C=4.95} \atop {3*H+2*C=5.45}} \right.$

Step-by-step explanation:

A system of equations is a set of two or more equations with several unknowns in which we want to find a common solution. So, a system of linear equations is a set of (linear) equations that have more than one unknown that appear in several of the equations. The equations relate these variables or unknowns to each other.

In this case, the unknown variables are:

H: price of a can of corn beef hash
C: price of a can of creamed chipped beef

Knowing the unit price of a product, the price of a certain quantity of that product is calculated by multiplying that quantity by the unit price. So the price for 2 cans of ground beef hash can be calculated as 2 * H and the price for 3 cans of ground beef with cream can be calculated as 3 * C. Jan paid $ 4.95 for those amounts from both cans. This means that the sum of the can prices must be $ 4.95. So: 2*H + 3*C= 4.95 Equation (A)

Thinking similarly, if Wayne bought 3 cans of corn beef hash and 2 cans of creamed chipped beef for $5.45, Wayne's buy can be expressed by the equation:

3*H + 2*C= 5.45 Equation (B)

Finally, the system of equations that models the problem is:

$\left \{ {{2*H+3*C=4.95} \atop {3*H+2*C=5.45}} \right.$

7 0

3 years ago