What can a denominator never be?
0
so, we need to figure what x can't be... the only way to multiply 2 things together to get 0 is if one or both are zero.
so, what x values make our denominator 0?
to figure this out, we need to set (x-1)(x-2)=0
now we split and solve.

so when x is 1 or 2 the function doesnt make sense.
but, x can be every other number and it does, so the answer is
ALL REAL NUMBERS not equal to 1 or 2
Answer:
B can be 1, 2, 4, 7, 8, 14, 28 and 56.
Basically any factor of 56.
Hope that helps!
<em>-scsb17hm</em>
Step-by-step explanation:
Answer:
the least common denominator
Step-by-step explanation:
The least common denominator is that number. It is the least common multiple of the denominator values.
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Simply multiplying by the product of the denominators will eliminate fractions, but may require reduction of fractions in the answer. If the "fractions" are rational expressions, extraneous solutions may be introduced.
The nonpermissible replacement is a value that make the denominator equal to zero
Since g(-x) is equal to g(x), the function is an EVEN FUNCTION.
<h3>Is the given function even, odd or neither?</h3>
Given the function in the question;
g(x) = (4 + x²)/(1 + x⁴)
To determine if the function is even, odd or neither, we find g(-x) by substituting -x for all occurrence of x in the function.
g(x) = (4 + x²)/(1 + x⁴)
g(-1) = (4 + (-x)²)/(1 + (-x)⁴)
Simplify
g(-x) = (4 + x²)/(1 + x⁴)
Hence,
g(-x) = g(x)
Since g(-x) is equal to g(x), the function is an EVEN FUNCTION.
Learn more about even functions here: brainly.com/question/23446734
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