<h3>
The dimensions of the given rectangular box are:</h3><h3>
L = 15.874 cm , B = 15.874 cm , H = 7.8937 cm</h3>
Step-by-step explanation:
Let us assume that the dimension of the square base = S x S
Let us assume the height of the rectangular base = H
So, the total area of the open rectangular box
= Area of the base + 4 x ( Area of the adjacent faces)
= S x S + 4 ( S x H) = S² + 4 SH ..... (1)
Also, Area of the box = S x S x H = S²H
⇒ S²H = 2000

Substituting the value of H in (1), we get:

Now, to minimize the area put :

Putting the value of S = 15.874 cm in the value of H , we get:

Hence, the dimensions of the given rectangular box are:
L = 15.874 cm
B = 15.874 cm
H = 7.8937 cm
The answer should be 834, 690
hope this helps!
Answer:
2j+1
Step-by-step explanation:
Circle the first symbol in front of the j's and 1's
Answer:
Breadth = 10 cm
Length = 15 cm
Step-by-step explanation:
Let the breadth = x cm
Length = (x + 5) cm
Perimeter of a rectangle = 50 cm
2 *( length + breadth) = 50
2*(x + 5 + x) = 50
Combine like terms
2*(2x + 5) = 50
2*2x + 2*5 = 50
4x + 10 = 50
Subtract 10 from both sides
4x = 50 - 10
4x = 40
Divide both sides by 4
x = 40/4
x = 10
Breadth = x = 10 cm
Length = x +5 = 10 + 5 = 15 cm