<span>The key step is to rewrite the exponential notations so that the exponent is the same. Then you can deal with the addition just as you would adding two decimals. The best way is to rewrite the number with the smaller exponent.
6.30 x 10^11 = 0.0630 x 10^13
Now you are adding 6.28 x 10^13 and 0.0630 x 10^13, and your answer is (6.28 + 0.0630) x 10^13. You can do the addition in the parentheses using the usual rules for sig dig when you add decimals. If necessary, afterward, you can rewrite the exponent again so that the mantissa is between 1 and 10.</span>
Answer: ab =6
have:
=> a + b + 1 = ab
⇔ a + b + 1 - ab = 0
⇔ b - 1 - a(b - 1) + 2 = 0
⇔ (b - 1)(1 - a) = -2
because a and b are postive integers => (b - 1) and (1 - a) also are integers
=> (b - 1) ∈ {-1; 1; 2; -2;}
(1 -a) ∈ {-1; 1; 2; -2;}
because (b -1).(1-a) = -2 => we have the table:
b - 1 -1 1 2 -2
1 - a 2 -2 -1 1
a -1 3 2 0
b 0 2 3 -1
a.b 0 6 6 0
because a and b are postive integers
=> (a;b) = (3;2) or (a;b) = (2;3)
=> ab = 6
Step-by-step explanation:
2 x 2 x 6 = 24ft²
1 x 2 x 12 = 24ft²
For this case we have the following equations:
5y = 3-2x
5y-3 = -2x
2x + 5y = 3
2x + 5y-3 = 0
The standard form of the equations is given by:
Ax + By = C
Therefore, the equation written in its standard form is:
2x + 5y = 3
Where,
A = 2
B = 5
C = 3
Answer:
The equation that is the standard form is:
2x + 5y = 3
Answer:
maybe like 5k
Step-by-step explanation:
