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LUCKY_DIMON [66]
3 years ago
8

A boy standing on the shore of a lake 1 mile wide wants to reach the fast-food restaurant 3 miles down the shore on the opposite

side of the lake. If he swims at 2 mph and walks at 4 mph, is it quicker for him to swim directly across the lake and walk to the restaurant or to swim directly to the restaurant? How much quicker? Explain.
Mathematics
1 answer:
evablogger [386]3 years ago
5 0

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2 x ² + 16x+63 2x² +19x+a​
PilotLPTM [1.2K]
=jeksjskakkjakakaaskskskskskskskdksk
5 0
3 years ago
Read 2 more answers
Occasionally an airline will lose a bag. Suppose a small airline has found it can reasonably model the number of bags lost each
julia-pushkina [17]

Answer:

a) The probability that the airline will lose no bags next monday is 0.1108

b) The probability that the airline will lose 0,1, or 2 bags next Monday is 0.6227

c) I would recommend taking a Poisson model with mean 4.4 instead of a Poisson model with mean 2.2

Step-by-step explanation:

The probability mass function of X, for which we denote the amount of bags lost next monday is given by this formula

P(X=k) = \frac{e^{-2.2} * {2.2}^k }{k!}

a)

P(X=0) = \frac{e^{-2.2} * {2.2}^0 }{0!} = 0.1108

The probability that the airline will lose no bags next monday is 0.1108.

b) Note that P(X \in \{0,1,2\} = P(X=0) + P(X=1) + P(X=2) . And

P(X=0)+P(X=1)+P(X=2) = e^{-2.2} * (1 + 2.2 + 2.2^2/2) = 0.6227

Therefore, the probability that the airline will lose 0,1, or 2 bags next Monday is 0.6227.

c) If the double of flights are taken, then you at least should expect to loose a similar proportion in bags, because you will have more chances for a bag to be lost. WIth this in mind, we can correctly think that the average amount of bags that will be lost each day will double. Thus, i would double the mean of the Poisson model, in other words, i would take a Poisson model with mean 4.4, instead of 2.2.

6 0
3 years ago
There is a total of 2,512 people attending the fun fair. 5/8 of sttemdees are students and 1/4 of attendees are parents. the res
kvv77 [185]

Answer:

<u>314 of the people attending the fun fair are people living in the neighborhood</u>

Step-by-step explanation:

1. Let's review the data given to us for solving the question:

Number of people attending the fun fair = 2,512

Fraction of people attending the fun fair that are students = 5/8

Fraction of people attending the fun fair that are parents = 1/4

Rest of the people attending the fun fair lives in the neighborhood

2. Let's calculate the number of students, parents and people living in the neighborhood

Students:

Fraction of people attending the fun fair that are students = 5/8

5/8 * 2,512 = 1,570

1,570 of the people attending the fun fair are students

Parents:

Fraction of people attending the fun fair that are parents = 1/4

1/4 * 2,512 = 628

628 of the people attending the fun fair are parents

People living in the neighborhood

2,512 - 1,570 - 628 = 314

<u>314 of the people attending the fun fair are people living in the neighborhood</u>

8 0
3 years ago
Solve for y.<br> A. 10 <br> B.12<br> C. 15<br> D. 18
djverab [1.8K]
Y=10°
If we're solving for the ninety degree angle, which I seem to doubt, then if 3x=90 then 2x=60 giving a missing total of 30. 30/3 equals 10
4 0
3 years ago
Read 2 more answers
PLEASE HELPP!!
Rasek [7]

Answer:

Given:

Two trail maps:

Trail on the first map = 8 cm

Trail on the second map = 6 cm

Scale on first map = 1 cm : 2 km

A) What is the scale factor from the map to the actual trail?

For the first map, the scale factor is 1 cm: 2km. Therefore the actual trail is 8 centimeters * 2 kilometers = 16 km.

The scale factor of the second map is 16 km / 6 cm = 2.67 km : 1 cm

B) The length of the actual trail is 16 kilometers.

Step-by-step explanation:

3 0
3 years ago
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